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3 years ago

What is the probability of getting a multiple of 8, in month of june?

Mathematics

2 answers:

Nadya [2.5K]3 years ago

6 0

The probability would be 3 days

Effectus [21]3 years ago

3 0

There are 30 days in June and only three of those days are multiples of 8 so you have the probability of 3 out of 30.

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PLLLLLLZZZZ HELP!! MULTIPLE CHOICE!!

liubo4ka [24]

First, set 2x+7 equal to 3x-7 since they are the same angle due to the parallel lines.

2x+7=3x-7
x=14

Then, since 2x+7 and 12y+1 equals 180, put it together to find y:

(2x+7)+(12y+1)=180
(2(14)+7)+(12y+1)=180
12y+1=145
12y=144
y=12

So, x=14 and y=12. Your answer should be C!

5 0

3 years ago

In a number with at least two digits, the last number was removed. The resulting number was n smaller than ghe previous one.

BartSMP [9]

Answer:

The largest possible value of n is 11.

(A) is correct option.

Step-by-step explanation:

Given that,

The number with at least two digits,the last number was removed. The resulting number was n smaller than the previous one.

We need to find the largest possible value of n

Using given data,

The smallest number of two digit is 10.

Now, we removed last digit then we get 1 which is equal to 10 divided 10.

So, n = 10

But the largest number of two digit is 99.

We removed last digit then we get 9 which is equal to 99 divided 11.

So, n = 11

Hence, The largest possible value of n is 11.

(A) is correct option.

5 0

3 years ago

DUE ASAP AT 10:30 5 ( x - 1 ) = 28 - 6x<br> A 3<br> B 7<br> C 10<br> D -7

Nostrana [21]

Answer:

Step-by-step explanation:

3 0

2 years ago

e) Given the following: Let X = {1, 2, 3, 4) and a relation R on X as R= {(1,2), (2,3), (3,4)}. Find the reflexive and transitiv

Naddika [18.5K]

Answer:

The answer is $\{(1,1),(2,2),(3,3),(4,4),(1,2)(2,3)(3,4),(1,3),(1,4)\}$

Step-by-step explanation:

Remember that a reflexive relation $R\subset \mathcal{P}(X)$ , where $\mathcal{P}(X)$ is the power set of $X$ , is one which conteins the ordered pairs of the form $(a,a)$ , for $a\in X$ .

So, As the reflexive and transitive closure of $R$ (that we will denote by $\overline{R}$ ) is in particular reflexive, we must add to $R$ the elements $\{(1,1) , (2,2),(3,3),(4,4) \}$

A transitive relation $R$ is one in which if the pair $(a,b)$ and the pair $(b,c)$ are in there, then the pair $(a,c)$ must be there too.

So, to complete the relation $R$ to be reflexive and transitive we must add the pair $(1,3)$ (because $(1,2),(2,3)$ are in $R$ ), the pair $(2,4)$ , and the pair $(1,4)$ because we added the pair $(2,4)$ .

Therfore we have that $\overline{R}=\{(1,1),(2,2),(3,3),(4,4),(1,2)(2,3)(3,4),(1,3),(1,4)\}$ .

6 0

3 years ago

Can someone please help me I’m not getting it

mr_godi [17]

The answer to the question is (-3,3)

8 0

3 years ago