Question 3 of 10

stiv31 [10]

Let's assign a variable that is the number when multiplied by 10% it is equal to 0.1.

Well let that be x.

Now we want to convert the 10% into a decimal. To convert a percent into a decimal, simply move the % sign two places to the left and make it into a decimal point.

When we say "of" in mathematics what we really mean is to multiply.

0.10 * x = 0.1

That is the equation we need to find the value of x for.

Divide both sides by 0.10

0.10 * x = 0.1

The 0.10 on the left side cancels out.

x = 1

So, the answer to this question is if we multiply 10% by 1 we will get 0.1.

7 0

3 years ago

Read 2 more answers

I need help fast like rn

lbvjy [14]

Answer:

vyuWYIRTG3ñwyiehg

Step-by-step explanation:

4 0

2 years ago

How do you find the legs of a right triangle when only given the hypotenuse?

tangare [24]

Answer:

We know that a^2+b^2=c^2. The 45° angle lets us know that y=x (45+45+90=180), so the problem is y^2+x^2=4sqrt of 2

$4 \sqrt{2} = \sqrt{32 } \\ \sqrt{32} ^{2} = 32$

So you get y^2+x^2=32, and from there, since we know x and y are equal, you can just divide 32 by 2 then take the square root of that, so the answer should be 4 for both x and y

Step-by-step explanation:

let me know if I'm wrong lol

6 0

2 years ago

Can someone help me plssss

lilavasa [31]

Answer:

To get the answer you need to understand the differences between the two in order to use common sense to get the answer

First you’ve got to calculate the inequality which is based on the weather

then look at the multiple choice questions and see which one represents the problem the best and that is… C.

8 0

2 years ago

Read 2 more answers

Determine whether a probability distribution is given. If a probability distribution is given, find its mean and standard deviat

drek231 [11]

Answer:

$E(X) = \sum_{i=1}^n X_i P(X_i) = 0*0.031 +1*0.156+ 2*0.313+3*0.313+ 4*0.156+ 5*0.031 = 2.5$

We can find the second moment given by:

$E(X^2) = \sum_{i=1}^n X^2_i P(X_i) = 0^2*0.031 +1^2*0.156+ 2^2*0.313+3^2*0.313+ 4^2*0.156+ 5^2*0.031 =7.496$

And we can calculate the variance with this formula:

$Var(X) =E(X^2) -[E(X)]^2 = 7.496 -(2.5)^2 = 1.246$

And the deviation is:

$Sd(X) = \sqrt{1.246}= 1.116$

Step-by-step explanation:

For this case we have the following probability distribution given:

X 0 1 2 3 4 5

P(X) 0.031 0.156 0.313 0.313 0.156 0.031

The expected value of a random variable X is the n-th moment about zero of a probability density function f(x) if X is continuous, or the weighted average for a discrete probability distribution, if X is discrete.

The variance of a random variable X represent the spread of the possible values of the variable. The variance of X is written as Var(X).

We can verify that:

$\sum_{i=1}^n P(X_i) = 1$

And $P(X_i) \geq 0, \forall x_i$

So then we have a probability distribution

We can calculate the expected value with the following formula:

$E(X) = \sum_{i=1}^n X_i P(X_i) = 0*0.031 +1*0.156+ 2*0.313+3*0.313+ 4*0.156+ 5*0.031 = 2.5$

We can find the second moment given by:

$E(X^2) = \sum_{i=1}^n X^2_i P(X_i) = 0^2*0.031 +1^2*0.156+ 2^2*0.313+3^2*0.313+ 4^2*0.156+ 5^2*0.031 =7.496$

And we can calculate the variance with this formula:

$Var(X) =E(X^2) -[E(X)]^2 = 7.496 -(2.5)^2 = 1.246$

And the deviation is:

$Sd(X) = \sqrt{1.246}= 1.116$

6 0

3 years ago