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Reptile [31]
3 years ago
9

A person uses a surfboard to ride every 30th wave crest towards the beach. The wave crest travels at a speed of 1.6m/s and the d

istance between each wave crest is 24 m. How many wave crests does the person surf in one hour?
Physics
1 answer:
pashok25 [27]3 years ago
6 0

Answer:

8

Explanation:

Applying,

v = λf................ Equation 1

Where v = velocity/ speed of the wave, λ = wave length of the wave, f = number of waves the person surf in one seconds.

make f the subject of the equation

f = v/λ............ Equation 2

From the question,

Given: v = 1.6 m/s, λ = 24 m

Substitute these values into equation 2

f = 1.6/24

f = 0.0667 wave/seconds.

If,

in one seconds, the person surf a total wave crest of 0.0667

Therefore,

in one hours, he will surf a total wave crest of (0.0667×60×60) = 240 waves crest

He rides for every 30th wave crest,

Hence,

number of wave crest the person surf in one hour = 240/30 = 8

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By counting the number of crests that pass in a given amount of time, a person can calculate the
ladessa [460]
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Hope this helps!
3 0
3 years ago
2. A 3 kg ball is thrown downward at 4 m/s from a height of 1.5 m. a. What is the kinetic energy of the ball as it leaves the th
ludmilkaskok [199]

Answer:

a) 24 J

b) Gravitational Force

c) 45 J

d) 0

e) 6.782m/s

Explanation:

a) m = 3kg

v = 4m/s

h = 1.5m

KE = ?

0.5 * 3 * 16 = 24J

b) Gravitational force

c) F = ma = 3 * 10 = 30N

Work done = Force * distance = 30 * 1.5 = 45J

d) Final Kinetic Energy of the ball is zero because the ball eventually stops moving

e) velocity of ball as it strikes the ground = v

v^{2} - u^{2} = 2as where

v is the velocity as it strikes the ground

u is the initial velocity

a is acceleration

s is the distance

Now since the ball is thrown downwards, a is positive because the velocity of the ball is increasing as the gravitational force acts on it

u = 4m/s

a = 10

s = 1.5

=>  v = \sqrt{2as + u^{2} }

= \sqrt{(2*10*1.5) + 16}

= \sqrt{46} = 6.782m/s

3 0
3 years ago
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