<h2>Answer:</h2><h2>The depth of barge float=
3 cm</h2><h2>
Explanation:</h2>
Length of rectangular barge=5.2 m
Width of rectangular barge=2.4m
Mass of crate=410 kg
Let h be the height of barge float
Volume of barge float=
Density of water=
Weight of water displaced by barge=Buoyant force=-Weight of horse



1 m=100 cm
cm
Hence, the depth of barge float=3 cm
<h2 />
You want to use PEMDAS to solve this equation.
4+9*2/3-1
4+18/6-1
4+6-1
10-1
9
Your answer is 9
Thanks -John
If you have anymore question just ask! :)
Yo sup??
The weight vector is usually drawn vertically downwards from the centre of the body.
It can be respectively resolved as well.
Hope this helps