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4 years ago

What's the difference between meteoroids, meteorites, and meteors?

1 answer:

4 0

You're talking about a grain of sand or a stone or a rock that's drifting in space, and then the Earth happens to get in the way, so the stone falls down to Earth, and it makes a bright streak of light while it's falling through the atmosphere and burning up from the friction.

-- While it's drifting in space, it's a meteoroid.

-- While it's falling through the atmosphere burning up and making a bright streak of light, it's a meteor.

-- If it doesn't completely burn up and there's some of it left to fall on the ground, then the leftover piece on the ground is a meteorite.

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A sheet of paper can be withdrawn from under a container of milk without toppling it if the paper is pulled A. gravity pulls ver

g100num [7]

C the milk carton has inertia
Inertia is an object not wanting to start moving when it's staying still, so the milk carton won't want to move and won't topple over

7 0

3 years ago

are the properties of a specific element the same as the properties of a molecule made up of that element ? why or why not

konstantin123 [22]

Because it’s science

8 0

4 years ago

Why was Galileo unable to successfully measure the speed of light?

il63 [147K]

Because every one of the sources of error in his experiment was bigger than what he was trying to measure.

Here's what he did, as I recall:

-- Galileo and his buddy took flashlights and hiked up two hilltops at night.

-- Galileo pointed his flashlight at his buddy on the other hill. Then he turned it on, and started his clock.

-- His buddy on the other hill pointed his flashlight at Galileo, and waited. When he saw the light from Galileo's flashlight, he turned HIS on.

-- When Galileo saw the light from his buddy's flashlight, he stopped his clock.

-- Galileo sent a message to his buddy: "Bel lavoro, amico. Andiamo alla taverna, ti offro una bibita fresca, e possiamo trovare ragazze."

Now, Galileo figured that the time shown on his clock was the time it took light to make the round trip from him to his buddy and back.

Yes, that was part of it. But there was probably also some time ...

-- between starting his clock and his flashlight,

-- between his buddy SEEing the light and STARTing his light,

-- between seeing his buddy's light and stopping the clock.

How much time could each of those add to the clock ? Well, one problem was that they couldn't be measured, and they were probably different every time the experiment. was repeated.

What do you think ? Could each of those reaction times be 0.1 second maybe ? So all together, there was an extra 0.3 seconds on the clock that had nothing to do with the light ?

Well, 0.3 seconds is about what light takes to travel almost 56,000 miles ! That's more than twice around the Earth !

If Galileo and his buddy were even 5 miles apart on their hilltops, their lights could make the round trip in something like 0.00005 second ! Those "reaction times" of theirs, adding a few tenths of a second on the clock, totally gummed up the experiment for sure. The thing that they were really trying to measure was ... as engineers say ... "lost in the noise".

4 0

3 years ago

When a fire breaks out, immediately use a fire extinguisher. true or false?

TEA [102]

The answer is true
Have a good day stay safe <3

7 0

3 years ago

A centripetal force of 5.0 newtons is applied to a rubber stopper moving at a constant speed in a horizontal circle. If the same

mezya [45]

Answer:

Both the frequency f and velocity v will increase.

When the radius reduces, the circumference of the circular path becomes smaller which means that more number of revolutions can be made per unit time as long as the force is kept constant; this is an increase in frequency.

Explanation:

The centripetal force acting on a mass in circular motion is given by equation (1);

$F_c=\frac{mv^2}{r}....................(1)$

where m is the mass of the object and r is radius of the circle. From equation one we see that the centripetal force is directly proportional to the square of the velocity and inversely proportional to the radius of the circular path.

However, according to the problem, the force is constant while the radius and the velocity changes. Therefore we can write the following equation;

$\frac{mv_1^2}{r_1}=\frac{mv_2^2}{r_2}......................(2)$

Also recall that m is constant so it cancels out from both sides of equation (2). Therefore from equation we can write the following;

$v_2=\sqrt{\frac{v_1^2r_2}{r_1}} .................(2)$

By observing equation (2) carefully, the ratio $\frac{r_2}{r_1}$ will with the square root increase $v_1$ since $r_2$ is lesser than $r_1$ .

Hence by implication, the value of $v_2$ will be greater than $v_1$ .

As the radius changes from $r_1$ to $r_2$ , the velocity also changes from $v_1$ to $v_2$ .

3 0

3 years ago