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3 years ago

The wavelength of a wave on a string is 1.2 meters. If the speed of the wave is 60 meters/second, what is its frequency?

Physics

2 answers:

maria [59]3 years ago

8 0

F=v/wavelength f=1.2/60=50Hz.

Radda [10]3 years ago

3 0

Answer : Frequency = 50 Hz

Explanation :

It is given that,

Wavelength of a wave on a string, $\lambda=1.2\ m$

The speed of the wave is, v = 60 m/s

We have to find the frequency of the wave.

We know that the speed of the wave is given by the product of the frequency of the wave and the wavelength.

$v=\nu \lambda$

$\nu=\dfrac{v}{\lambda}$

$\nu=\dfrac{60\ m/s}{1.2\ m}$

$\nu=50\ Hz$

So, the frequency of the wave is 50 Hz.

Hence, this is the required solution.

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valkas [14]

Answer:

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3 years ago

Does the thickness of the wire affect the strength of an electroscope

TiliK225 [7]

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3 years ago

I have a picture of the question I need help with,

eduard

Given:

The initial velocity of the object, v=30 m/s

a_t=0

a_c≠0

The time period is Δt.

To find:

The right conclusion among the given choices.

Explanation:

a_t represents the tangential accleration on the object and a_c represents the centripetal acceleration on the object.

The centripetal acceleration is the acceleration that keeps the object in its circular path. The centripetal force only changes the direction of the velocity and not the magnitude.

Thus the magnitude of the velocity of the object remains the same after a time interval of Δt. But the direction of the velocity of the object will be changed and will be unknown after Δt seconds.

Final answer:

Thus the object will be traveling at 30 m/s in some unknown direction.

Therefore, the correct answer is option a.

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9 months ago

What is the angle of deviation in a plane mirror at normal incidence?

Tems11 [23]

Answer:

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3 years ago

sara and tory are out fishing on the lake on a hot summer day when they both decide to go for a swim. sara dives off the front o

crimeas [40]

Here it is an application of Newton's III law

as we know by Newton's III law that every action has equal and opposite reaction

So here as we know that two boys jumps off the boat with different forces

from front side of the boat the boy jumps off with force 45 N which means as per Newton's III law if boy has a force of 45 N in forward direction then he must apply a reaction force on the boat in reverse direction of same magnitude

So boat must have an opposite force on front end with magnitude 45 N

Now similar way we can say

from back side of the boat the boy jumps off with force 60 N which means as per Newton's III law if boy has a force of 60 N in backward direction then he must apply a reaction force on the boat in reverse direction of same magnitude

So boat must have an opposite force on front end with magnitude 60 N

So here net force due to both jump on the boat is given by

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$F_{net} = 60 - 45$

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so boat will have net force F = 15 N in forward direction due to both jumps

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3 years ago