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3 years ago

15

I know no ones is gonna see this, but I'm desperate and I'm just overall done with my day. But ill give it a shot, please help m

e solve this.

2 answers:

nadya68 [22]3 years ago

7 0

If the angle is 45° then the sides are equal. Both x and y is 14 sqrt(2)

sladkih [1.3K]3 years ago

5 0

Answer:

show me the dentist appointment Leventhal and a toothache now

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Rewrite in radical form (-243)2/5

nadezda [96]

Answer:

243 and 2 over 5

Multiply

(−243) and 2 over 5 . −486 over 5.

Move the negative in front of the fraction.

−486 over 5

Exact Form:

-486 over 5

Decimal Form:

-97.2

Mixed Number Form:

-97 and 1 over 5

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3 years ago

What is the value of g^(2)? <br> A. -1 B. 1 C. 2 D. 1/2

kvasek [131]

Answer:

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Step-by-step explanation:

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3 years ago

What is the trigonometric derivative of Y=2sinx-tanx

Alchen [17]

$\bf y=2sin(x)-tan(x)\implies \cfrac{dy}{dx}=2cos(x)-sec^2(x)$

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3 years ago

Use identities to find the values of the sine and cosine functions for the following angle measure.

puteri [66]

Using the cosine double angle formula,

$\cos 2\theta=2\cos^2 \theta-1=\frac{12}{13}\\\\2\cos^{2} \theta=\frac{25}{13}\\\\\cos^{2} \theta=\frac{25}{26}\\\\\boxed{\cos \theta=\frac{5}{\sqrt{26}}}$

(Note I took the positive case since $\theta$ terminates in the first quadrant)

Using the Pythagorean identity,

$\sin^2 \theta+\cos^2 \theta=1\\\\\sin^2 \theta+\frac{25}{26}=1\\\\sin^2 \theta=\frac{1}{26}\\\\\boxed{\sin \theta=\frac{1}{\sqrt{26}}}$

(Note I took the positive case since $\theta$ terminates in the first quadrant)

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1 year ago

Is a cube a polygon? Why or why not?

SOVA2 [1]

No, because a polygon has to be vertical and a cube is straight.

4 0

4 years ago

Read 2 more answers