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-Dominant- [34]
4 years ago
15

Which of these is one way that mechanical waves differ from electromagnetic waves?

Chemistry
2 answers:
djyliett [7]4 years ago
8 0

Answer:

Mechanical waves require a medium and electromagnetic waves do not.  

Explanation:

Electromagnetic waves are essentially a combination of electric and magnetic fields produced by the motion of charged particles. They do not require a medium to travel and can simply propagate through space. For example, light waves are electromagnetic waves

Mechanical waves are energy waves that are produced by inducing a certain disturbance in a medium. These waves require a medium to propagate and cannot travel in empty space. For example, sound waves are mechanical waves.

Softa [21]4 years ago
6 0

Electromagnetic waves differ from mechanical waves in that they do not require a medium to propagate. This means that electromagnetic waves can travel not only through air and solid materials, but also through the vacuum of space.

Mechanical waves require a medium and electromagnetic waves do not.

Hope this helps :)

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An aluminum cup of 140 cm3 capacity is completely filled with glycerin at 20°C. How much glycerin will spill out of the cup if t
mel-nik [20]

Explanation:

The given data is as follows.

    coefficient of volume expansion of glycerin (\beta) = 5.1 \times 10^{-4} 1/^{o}C

     linear expansion coefficient of aluminum, (\alpha_{A}) = 23 \times 10^{-6} 1/^{o}C  

              Volume = 100 cm^{3}

The increase in volume of the cup will be calculated as follows.

                    \Delta V_{c} = V \times 3 \times \alpha \times \Delta T

                                 = 100 cm^{3} \times 3 \times 23 \times 10^{-6} \times (31 - 20)^{o}C

                                 = 75900 \times 10^{-6} cm^{3}

                                 = 0.0759 cm^{3}

Formula for increase in volume  of glycerine is as follows.

               \Delta V_{g} = V \times \beta_{g} \times \Delta T

                              = 100 cm^{3} \times 5.1 \times 10^{-4} 1/^{o}C \times (31 - 20)^{o}C

                              = 0.5610 cm^{3}

Therefore, volume of glycerin spilled is calculated as follows.

                        \Delta V = \Delta V_{g} - \Delta V_{c}

                                     = (0.5610 - 0.0759) cm^{3}

                                     = 0.4851 cm^{3}

Thus, we can conclude that 0.4851 cm^{3} glycerin will spill out of the cup.

6 0
3 years ago
What is the pressure in a container that has 3 atm H2, 2 atm of N2 and 5 atm of F2?
LekaFEV [45]
<h3>Pressure has additive properties meaning that if you add the partial pressures together, you obtain total pressure.  P total = P1 + P2 + P3 + ...  Pressure of container = pressure of H2 + Pressure of N2 + Pressure of F2                                          = 3atm + 2atm + 5atm                                                        = 10atm    Hope that helped. ;)</h3>
7 0
3 years ago
A volume of 2.15 mL of Oxygen was collected in the lab at a temperature of 17 °C and 740.2 mmHg. After a day, the volume of the
Maurinko [17]

The new temperature (T₂) in the lab = 25.09 °C

<h3>Further explanation</h3>

Given

V₁=2.15 ml

T₁ = 17 + 273 = 290 K

P = 740.2 mmHg

V₂ = 2.21 ml

Required

The new temperature (T₂)

Solution

Charles's Law

<em>When the gas pressure is kept constant, the gas volume is proportional to the temperature </em>

\tt \dfrac{V_1}{T_1}=\dfrac{V_2}{T_2}

Input the value :

T₂=(T₁.V₂)/V₁

T₂=(290 K x 2.21 ml)/2.15 ml

T₂=298.09 K = 25.09 °C

8 0
3 years ago
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Mkey [24]

Answer:

98.07848 grams.

Explanation:

6 0
3 years ago
To use patterns in observations to say what may happen next
PilotLPTM [1.2K]
In order to know what may happen next you need use patterns in the observation
5 0
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