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IgorC [24]
3 years ago
11

Should a mortar and pestle should be used for grinding only one substance at a time

Chemistry
1 answer:
MatroZZZ [7]3 years ago
8 0
The mortar and pestle is most commonly used in chemical laboratories or in the kitchen. Its key function is to grind the material into smaller pieces, usually into its powdered form. It looks like that shown in the picture. The mortar is the bowl in which the material to be pounded is placed, and the pestle does the pounding.

Now, when you ask if it can only pound one at a time, my honest answer is, it depends. Depending on the size of your mortar, you could grind materials two or three at a time. But if you are concerned with contamination, then you do it one at a time, especially if you don't want them to get mixed up.

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How much voltage is required to run 1.6 A of current through a 240
pentagon [3]

Answer:

answer is not there

Explanation:

V=1.6×240

V=384volt

6 0
2 years ago
An electron in the n = 3 energy level of the hydrogen atom emits a photon with wavelength 656.27 nm. What is the change in energ
Lady_Fox [76]

Answer:change in energy of the electron=3.052x 10^-19J

which energy level does it move= level 2 , n=2

Explanation:

Using the formulae

1/λ = R (1/n1²- 1/n2²)

Where λ= 656.27 nm

1 nm = 1 x 10^-9 m

656.27 nm = 656.27 x 1 x 10^-9 =6.5726 x 10^-7

R =Rydberg constant = 1.0967 x 10^7m-1

1/λ = R (1/n1²- 1/n2²)

1/6.5726 x 10^-7=1.0967 x 10^7(1/n1²- 1/3²)

1/n1²=(1/6.5726 x 10^-7 x   1/1.0967 x 10^7) + 1/9

1/n1²=1,521,467.9 x 9.118x10^-8 + 0.1111

1/n1² =0.2498

n1²= 1/0.2498 =4

n1= \sqrt{4} = 2

it moves to energy level 2

b) Change in energy =ΔE = Rhc (1/n1²- 1/n2²)

Where R==Rydberg constant = 1.0967 x 10^7m-1

h = Planck constant = 6.626x 10^-34js

c = speed of light = 3.0 x 10^8 x m/s

ΔE = Rhc (1/n1²- 1/n2²)

=1.0967 x 10^7m-1 x6.626x 10^-34js X 3.0 x 10^8 x m/s (1/2² - 1/3²)

=2.18 x 10-18 x ( 1 /4 - 1/9)

=3.052x 10^-19J

7 0
3 years ago
PLEASE HELP!! I need these before 12!
Aloiza [94]

Answer:

1. 32

2. 28

3. 46

4. 57

5. 13

6. 32

7. 21

Explanation:

8 0
3 years ago
How much heat is gained by 1.25 grams of ice?
vivado [14]

Answer:

Heat  gained by 1.25 grams of ice is 250 joules

Explanation:

As we know

Q = mc\DeltaT

Where

\DeltaT is the change in temperature

Water freezes at 273.15 K/0 degree Celsius, and it boils at 373.15 K/00 degree Celsius,

\DeltaT  

m is the mass in grams

c is the specific heat of water (ice) = 2.05 joules/gram

Substituting the given values, we get -

Q = 1.25 * 2.0 * 100\\Q = 250Joules.

8 0
3 years ago
241 san sotope of plutonium that is highly radioactive and is used in some nuclear reactors and many nuclear weapons.
postnew [5]

Answer:

your answer is the third option

8 0
3 years ago
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