- All the listed combination of row and boxes are correct and can be chosen from.
From the question, we are asked to find the row arrangement of a stack of boxes. Let us take a look at each one of the aforelisted answers
- x rows with 16 boxes in each row
- 8 rows with x boxes in each row
- 16 rows with x boxes in each row
Since we are told that the total number of boxes to be stacked is 64, then for the first arrangement, we can deduce that the "x" is going to be 4. This is because multiplying 4 by 16 gives 64. For the second row, using the same calculation, we find that "x" is 8. And that of the third gives our "x" to be 4 as well. We can then adjudge that;
- 4 rows with 16 boxes in each row
- 8 rows with 8 boxes in each row
- 16 rows with 8 boxes in each row
Bearing this in mind, we can see that each of the 3 answers fits into the requirements we are asked.
- At least 3 rows, and at least 4 boxes in each row.
Hence, all of the options are correct.
To learn more about rows and columns, see here brainly.com/question/13196178
Answer:
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Step-by-step explanation:
Answer:
<h2>A.) 3 6/8</h2>
Step-by-step explanation:
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Answer: 
Step-by-step explanation:
The exponent 1/3 is the same thing as cube rooting the expression.
![\sqrt[3]{27\sqrt[3]{z^2} }](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B27%5Csqrt%5B3%5D%7Bz%5E2%7D%20%7D)
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Hope it helps <3
If we convert the given in its mathematical form, we have,
(30x⁶/14y⁵)(7y²/6x⁴)
It can be observed that the numerator of the first and the denominator of the second have a common factor of 6x⁴. Also, the denominator of the first and the numerator of the second expression have a common factor of 7y².
((6x⁴)(5x²)/(7y²)(2y³))(7y²/6x⁴)
Cancellation of the common terms will give us an answer of,
<em>5x²/2y³
</em><em />Therefore, the simplified version of the involved operation is 5x²/2y³. <em>
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