3 years ago

Please help a fella out

Mathematics

2 answers:

svetoff [14.1K]3 years ago

7 0

0.000000783 in scientific notation is 7.83 x 10^-7

lutik1710 [3]3 years ago

7 0

0.000000783 written in scientific notation is 7.83 x 10^-7

Hope this helps

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(2pm^-1q^0)^-4 • 2m ^-1 p^3 / 2pq^2

Montano1993 [528]

Answer:

$\dfrac{m^3}{16p^2q^2}$

Step-by-step explanation:

Given:

$(2pm^{-1}q^0)^{-4}\cdot \dfrac{ 2m^{-1} p^3}{2pq^2}$

$m^{-1}=\dfrac{1}{m}$

$q^0=1$

$2pm^{-1}q^0=2p\cdot \dfrac{1}{m}\cdot 1=\dfrac{2p}{m}$

$(2pm^{-1}q^0)^{-4}=\left(\dfrac{2p}{m}\right)^{-4}=\left(\dfrac{m}{2p}\right)^4=\dfrac{m^4}{(2p)^4}=\dfrac{m^4}{16p^4}$

$m^{-1}=\dfrac{1}{m}$

$2m^{-1} p^3=2\cdot \dfrac{1}{m}\cdot p^3=\dfrac{2p^3}{m}$

$\dfrac{ 2m^{-1} p^3}{2pq^2}=\dfrac{\frac{2p^3}{m}}{2pq^2}=\dfrac{2p^3}{m}\cdot \dfrac{1}{2pq^2}=\dfrac{p^2}{mq^2}$

$(2pm^{-1}q^0)^{-4}\cdot \dfrac{ 2m^{-1} p^3}{2pq^2}=\dfrac{m^4}{16p^4}\cdot \dfrac{p^2}{mq^2}=\dfrac{m^3}{16p^2q^2}$

8 0

3 years ago

The faces of a fair cube are numbered 1 through 6; the probability of rolling any number from 1 through 6 is equally likely. If

Anika [276]

Answer:

1/12

Step-by-step explanation:

Probability of an even number

3/6 = 1/2

Probability of one showing up

1/6

Probably of even number on first try and 1 on second try

1/2 * 1/6 = 1/12

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3 years ago

Solve for y<br> 5x + y = -10

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You would subtract 5x from y so y=5x-10

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3 years ago

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Zanier has a cap box. The box contains 7 blue caps, 5 green caps, and 8 pink caps. Without looking, if zanier chooses a cap from

attashe74 [19]

Answer:

5/20

Step-by-step explanation:

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3 years ago

When q= -4 and g=1 look at picture

jeka94

Answer:

-25

Step-by-step explanation:

sorry for the mistake

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3 years ago