The Alternate Interior Angle theorem states that when the lines are parallel, the alternate interior angles are equal. Since lines AB and CD are parallel, m∠ACD and m∠BAC are equal. So, the equation would be 
or 
.
Please help a fella out
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2x - y = 5
x + 3y = 7
I'm assuming you mean the coefficient matrix.
![\left[\begin{array}{ccc}2&-1\\1&3\end{array}\right] =(2)(3)-(-1)(1)=6+1=7](https://tex.z-dn.net/?f=%20%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D2%26-1%5C%5C1%263%5Cend%7Barray%7D%5Cright%5D%20%3D%282%29%283%29-%28-1%29%281%29%3D6%2B1%3D7)
x + 3y = 7
I'm assuming you mean the coefficient matrix.
Given:
Total number of calculators in a box = 10
Defective calculators in the box = 1
To find:
The number of ways in which four calculators be selected and one of the four calculator is defective.
Solution:
We have,
Total calculators = 10
Defective calculators = 1
Then, Non-defective calculator = 10-1 = 9
Out of 4 selected calculators 1 should be defective. So, 3 calculators are selected from 9 non-defective calculators and 1 is selected from the defective calculator.
Therefore, the four calculators can be selected in 84 ways.