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3 years ago

Find the percentage decrease when 94 decreases to 23.5

Mathematics

2 answers:

AveGali [126]3 years ago

4 0

Answer:

75%

Step-by-step explanation:

(94-23.5)/(94)*100=75%

lora16 [44]3 years ago

4 0

'Percent (%)' means 'out of one hundred':

p% = p 'out of one hundred',

p% is read p 'percent',

p% = p/100 = p ÷ 100.

23.5% = 23.5/100 = 23.5 ÷ 100 = 0.235.

100% = 100/100 = 100 ÷ 100 = 1.

Decrease number by 23.5% of its value.

Percentage decrease = 23.5% × 94

New value = 94 - Percentage decrease

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3 years ago

Y=6x-1, y=3x-4 the solution is_____

TEA [102]

Answer:

y= -7 and x= -1

Step-by-step explanation:

To do this, line up the variables so it looks like this...

y-6x=-1

y-3x=-4

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3 years ago

Complete the ratio- I WILL GIVE BRAINLIEST TO WHOEVER ANSWERS FIRST!<br><br> 8:44=1::?

miskamm [114]

Answer:

8 /8 =1

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3 0

3 years ago

2/13 divided by 1/6 need help

tia_tia [17]

Dividing by a fraction means the same as multiplying by its reciprocal.

In other words, change the division sign to multiplication

and flip or take the reciprocal of the second fraction.

So we can rewrite 2/13 ÷ 1/6 as 2/13 × 6/1.

Now multiply across the numerators and denominators to get 12/13.

8 0

3 years ago

Read 2 more answers

Examine the required sample size needed to be able to

Xelga [282]

Answer:

$n=(\frac{2.33(500)}{10})^2 =13572.25 \approx 13573$

And if we use a sample level of n =2000 the margin of error would be higher as we can see here:

$ME=2.33\frac{500}{\sqrt{2000}}=26.05$

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

$\bar X$ represent the sample mean for the sample

$\mu$ population mean (variable of interest)

$\sigma=500$ represent the population standard deviation assumed

n represent the sample size (variable of interest)

Confidence =98% or 0.98

ME = 10 represent the margin of error desired

The margin of error is given by this formula:

$ME=z_{\alpha/2}\frac{\sigma}{\sqrt{n}}$ (a)

And on this case we have that ME =10 and we are interested in order to find the value of n, if we solve n from equation (a) we got:

$n=(\frac{z_{\alpha/2} \sigma}{ME})^2$ (b)

The critical value for 98% of confidence interval now can be founded using the normal distribution. And in excel we can use this formla to find it:"=-NORM.INV(0.01;0;1)", and we got $z_{\alpha/2}=2.33$ , replacing into formula (b) we got:

$n=(\frac{2.33(500)}{10})^2 =13572.25 \approx 13573$

So the answer for this case would be n=13573 rounded up to the nearest integer

And if we use a sample level of n =2000 the margin of error would be higher as we can see here:

$ME=2.33\frac{500}{\sqrt{2000}}=26.05$

3 0

4 years ago

Find the percentage decrease when 94 decreases to 23.5​

Find the percentage decrease when 94 decreases to 23.5