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3 years ago

Which function has an inverse that is a function?

Mathematics

1 answer:

statuscvo [17]3 years ago

3 0

Answer:

i aint never seen two pretty bestfriends

Step-by-step explanation:

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URGENT HELP! URGENT I WILL GIVE ALL OF MY POINTS

anastassius [24]

Answer:

false, true, false

Step-by-step explanation:

6 0

3 years ago

Read 2 more answers

The charity gala costs $5.17 for every attendee. How many attendees can there be, at most, if the budget for the charity gala is

Elodia [21]

Answer:

15 people are able to be at the charity gala because 77:55 divided by 5:17.

3 0

3 years ago

Write in standard form: 22.2 x 10^5

garri49 [273]

2220000

it just means that 22.2 needs to be multiplied by 10, 5 times, so just move the decimal five to the right.

3 0

3 years ago

Each school bus going on the field trip holds 36 students and for adults there are six Fields buses on the field trip how many p

BartSMP [9]

Answer:

240 people

Step-by-step explanation:

According to the given data,

In each bus,there are total number of 36 students and 4 adults

So, total 40 people are in one bus so...

As, there are six Fields buses

=>40 x 6

=240

Answer: Total 240 people are going on the field trip.

5 0

4 years ago

Find the indefinite integral using the substitution provided.

Nady [450]

Answer: $7\text{Ln}\left(e^{2x}+10\right)+C$

This is the same as writing 7*Ln( e^(2x) + 10) + C

=======================================================

Explanation:

Start with the equation $u = e^{2x}+10$

Apply the derivative and multiply both sides by 7 like so

$u = e^{2x}+10\\\\\frac{du}{dx} = 2e^{2x}\\\\7\frac{du}{dx} = 7*2e^{2x}\\\\7\frac{du}{dx} = 14e^{2x}\\\\7du = 14e^{2x}dx\\\\$

The "multiply both sides by 7" operation was done to turn the 2e^(2x) into 14e^(2x)

This way we can do the following substitutions:

$\displaystyle \int \frac{14e^{2x}}{e^{2x}+10}dx\\\\\\\displaystyle \int \frac{1}{e^{2x}+10}14e^{2x}dx\\\\\\\displaystyle \int \frac{1}{u}7du\\\\\\\displaystyle 7\int \frac{1}{u}du\\\\\\$

Integrating leads to

$\displaystyle 7\int \frac{1}{u}du\\\\\\7\text{Ln}\left(u\right)+C\\\\\\7\text{Ln}\left(e^{2x}+10\right)+C\\\\\\$

Be sure to replace 'u' with e^(2x)+10 since it's likely your teacher wants a function in terms of x. Also, do not forget to have the plus C at the end. This is a common mistake many students forget to do.

To verify the answer, you can apply the derivative to it and you should get back to the original integrand of $\frac{14e^{2x}}{e^{2x}+10}$

4 0

2 years ago