What is the molarity of a solution preparedby dissolving 10.0 g of acetone, C3H6O, in enough water to make 125 mL of solution?
1 answer:
Answer:
1.379 M
Explanation:
The computation of the molarity of a solution is as follows;
As we know that
Molarity(M) = number of moles of solute ÷ volume of solution ( in L )
Given that
Mass = 10 grams
Molar mass of acetone(C3H6O) = 58 g/mol
moles = mass ÷ molar mass
= 10 g ÷ 58 g/mol
= 0.172414 mol
Now the molarity of the solution is
Volume of solution = 125 mL = 0.125 L
As
1 L = 1000 mL
so,
125 mL = (125 mL × ( 1 L ÷ 1000 mL) = 0.250 L)
Now the molarity is
= 0.172414 mol ÷ 0.125 L
= 1.379 M
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