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Y_Kistochka [10]
3 years ago
5

Suppose a cobalt atom in the oxidation state formed a complex with two bromide anions and four ammonia molecules. Write the chem

ical formula of this complex.
Chemistry
1 answer:
Katena32 [7]3 years ago
4 0

Complete Question:

Suppose a cobalt atom in the +3 oxidation state formed a complex with two bromide (Br-) anions and four ammonia (NH3) molecules. write the chemical formula of this complex.

Answer:

[Co(NH₃)₄]⁺Br₂

Explanation:

The cobalt atom with +3 oxidation is represented as Co⁺³, and if it's bonded to two bromide ions, and four ammonia molecules. The molecules that are bonded to the metal atom (Co) are called complexing agents.

In the representation, we first put the molecules that surround the metal atom, forming an anion with the oxidation of the metal:

[Co(NH₃)₄]⁺³

Then, the ions are put in the formula. Because there are two bromides ion, each one with 1 minus charge, only 2 plus charged will be neutralized, and the complex will be:

[Co(NH₃)₄]⁺Br₂

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Answer:

remain the same

Explanation:

The pH of the buffer system remain the same when 0.030 moles of strong acid are added because buffer system has the property to resist any change in the pH  when acid or base is added to the solution. In buffer system, one molecule is responsible for neutralizing the pH of the solution by giving H+ or OH-.This molecule is known as buffer agent. If more base is added, the molecule provide H+ and when more acid is added to the solution, then the molecule add OH- to the solution.

7 0
4 years ago
A student decreases the temperature of a 556 c m cubed balloon from 278 K to 231 K. Assuming constant pressure, what should the
a_sh-v [17]

Answer:

The new volume of the balloon be 462\ cm^3.

Explanation:

We have,

Initial volume is 556 cm ³

The temperature of the balloon decreases from 278 K to 231 K.

We need to find the new volume of the balloon if the pressure is constant.

The Charles law states that at constant pressure, the volume of gas is directly proportional to its temperature i.e.

V\propto T, P is constant

\dfrac{V_1}{V_2}=\dfrac{T_1}{T_2}

V_2=\dfrac{V_1T_2}{T_1}\\\\V_2=\dfrac{556\times 231}{278}\\\\V_2=462\ cm^3

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3 0
3 years ago
How many significant figures does the following number contain: 385.01
dusya [7]

Answer:

5 significant figures

Explanation:

  • Zeros that come before any non-zero digits are never significant.

  • Zeros that are in between any non-zero digits are always significant.

  • Zeros that come after any non-zero digit are ONLY significant if a decimal point in present somewhere in the number. (In this case there is a decimal point, but there aren't any zeros at the end of this number.)

I have underlined the significant figures in this number:

<u>3</u> <u>8</u> <u>5</u> . <u>0</u> <u>1</u>

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4 years ago
A chemist needs 2.00 liters of hydrochloric acid. How many pints is this?
77julia77 [94]
Is that supposed to say 200/2.00??
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Hydrogen sulfate reacts with water to produce sulfate ions and hydronium ions: hso4−+h2o⇌so42−+h3o+ identify the conjugate acid-
Angelina_Jolie [31]
The generic equation for a reaction between an acid and water is 

     HX_{(aq)} + H_{2}O_{(aq)} --> X_{(aq)}^{-} + H_{3}O_{(aq)}^+

When an acid "reacts" with water, water acts as the base that accepts the proton (H+) from the acid. The remaining ion that is formed after the acid has donated its proton is called the conjugate base (X^-), and the conjugate acid-base pair is HX - X^-. 

Hydrogen sulfate (HSO_{4}^-) is an ion from sulfuric acid. It is still an acid in itself and can "react" with water ((H_{2}O) to form the sulfate (SO_{4}^2-) and hydronium (H_{3}O^+)ions. 

HSO_{4(aq)}^{-} + H_{2}O_{(aq)} --> SO_{4(aq)}^{2-} + H_{3}O_{(aq)}^+

Based on the previous discussion, SO_{4(aq)}^2- is identified to be the conjugate of the acid HSO_{4(aq)}^-. Thus, the conjugate acid-base pair is HSO_{4(aq)}^{-} - SO_{4(aq)}^{2-}.
8 0
3 years ago
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