Answer:
remain the same
Explanation:
The pH of the buffer system remain the same when 0.030 moles of strong acid are added because buffer system has the property to resist any change in the pH when acid or base is added to the solution. In buffer system, one molecule is responsible for neutralizing the pH of the solution by giving H+ or OH-.This molecule is known as buffer agent. If more base is added, the molecule provide H+ and when more acid is added to the solution, then the molecule add OH- to the solution.
Answer:
The new volume of the balloon be
.
Explanation:
We have,
Initial volume is 556 cm ³
The temperature of the balloon decreases from 278 K to 231 K.
We need to find the new volume of the balloon if the pressure is constant.
The Charles law states that at constant pressure, the volume of gas is directly proportional to its temperature i.e.
, P is constant


So, the new volume of the balloon be
.
Answer:
5 significant figures
Explanation:
- Zeros that come before any non-zero digits are never significant.
- Zeros that are in between any non-zero digits are always significant.
- Zeros that come after any non-zero digit are ONLY significant if a decimal point in present somewhere in the number. (In this case there is a decimal point, but there aren't any zeros at the end of this number.)
I have underlined the significant figures in this number:
<u>3</u> <u>8</u> <u>5</u> . <u>0</u> <u>1</u>
Is that supposed to say 200/2.00??
The generic equation for a reaction between an acid and water is

When an acid "reacts" with water, water acts as the base that accepts the proton (H+) from the acid. The remaining ion that is formed after the acid has donated its proton is called the conjugate base (

), and the conjugate acid-base pair is

-

.
Hydrogen sulfate (

) is an ion from sulfuric acid. It is still an acid in itself and can "react" with water ((

) to form the sulfate (

) and hydronium (

)ions.

Based on the previous discussion,

is identified to be the conjugate of the acid

.
Thus, the conjugate acid-base pair is
.