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4 years ago

Read the following chemical equation

Chemistry

1 answer:

Naddika [18.5K]4 years ago

8 0

Answer:

For eacht 4 moles Fe consumed, we will produce 2 moles Fe2O3

The mole ration is 4:2 (option 1)

Explanation:

Step 1: The unbalanced equation

Fe + O2 → Fe2O3

Step 2: Balancing the equation

Fe + O2 → Fe2O3

On the left side we have 2x O (in O2) and on the right side we have 3x O (in Fe2O3) . To balance the amount of O on both sides, we have to multiply O2 by 3 and Fe2O3 by 2.

Fe + 3O2 → 2Fe2O3

On the left side we have 1x Fe, On the right side we have 4x (in 2Fe2O3). To balance the amount of Fe we have to multiply Fe (on the left side) by 4.

Now the equation is balanced.

4Fe + 3O2 → 2Fe2O3

For eacht 4 moles Fe consumed, we will produce 2 moles Fe2O3

The mole ration is 4:2 (option 1)

You might be interested in

How does distillation work.

Usimov [2.4K]

Answer:

Distillation is an important commercial process that is used in the purification of a large variety of materials. However, before we begin a discussion of distillation, it would probably be beneficial to define the terms that describe the process and related properties. ... Elevation of the boiling point with an increase in external pressure, while important in cooking and sterilizing food or utensils, is less important in distillation.

Explanation:

8 0

2 years ago

An equilibrium mixture of PCl 5 ( g ) , PCl 3 ( g ) , and Cl 2 ( g ) has partial pressures of 217.0 Torr, 13.2 Torr, and 13.2 To

antoniya [11.8K]

Answer: The new partial pressures of $PCl_5,PCl_3\text{ and }Cl_2$ when equilibrium is re-established are 223.4 torr, 6.82 torr and 26.4 torr respectively.

Explanation:

For the given chemical reaction:

$PCl_3(g)+Cl_2(g)\rightleftharpoons PCl_5(g)$

The expression of $K_p$ for above reaction follows:

$K_p=\frac{P_{PCl_5}}{P_{PCl_3}\times P_{Cl_2}}$ ........(1)

We are given:

$P_{PCl_5}=217.0torr$

$P_{PCl_3}=13.2torr$

$P_{Cl_2}=13.2torr$

Putting values in above equation, we get:

$K_p=\frac{217.0}{13.2\times 13.2}\\\\K_p=1.24$

Now we have to calculate the new partial pressure of $Cl_2$ .

$P_{PCl_5}+P_{PCl_3}+P_{Cl_2}=P_{Total}$

$217.0torr+13.2torr+P_{Cl_2}=263.0torr$

$P_{Cl_2}=32.8torr$

The reaction is re-established and proceed to right direction by Le-Chatelier's principle to cancel the effect of addition of $Cl_2$ .

Now, the equilibrium is shifting to the reactant side. The equation follows:

$PCl_3(g)+Cl_2(g)\rightleftharpoons PCl_5(g)$

Initial: 13.2 32.8 217.0

At eqm: 13.2-x 32.8-x 217.0+x

Putting values in expression 1, we get:

$1.24=\frac{(217.0+x)}{(13.2-x)(32.8-x)}\\\\x=40.4,6.38$

Neglecting the 40.4 value of 'x' because pressure can not be more than initial partial pressure.

Thus, the value of 'x' will be, 6.38 torr.

Now we have to calculate the new partial pressures after equilibrium is reestablished.

Partial pressure of $PCl_5$ = (217.0+x) = (217.0+6.38) = 223.4 torr

Partial pressure of $PCl_3$ = (13.2-x) = (13.2-6.38) = 6.82 torr

Partial pressure of $Cl_2$ = (32.8-x) = (32.8-6.38) = 26.4 torr

Hence, the new partial pressures of $PCl_5,PCl_3\text{ and }Cl_2$ when equilibrium is re-established are 223.4 torr, 6.82 torr and 26.4 torr respectively.

7 0

3 years ago

How many kilojoules are released when 2.25 mol of H2O2 reacts?

Stels [109]

Answer:

230.3 kJ

Some chemical reactions show release of heat while some show absorption of heat. On these bases, the reaction is classified as either endothermic or exothermic. Negative sign of ΔH means exothermic reaction.

8 0

3 years ago

HELP PLZ ASAP I NEED IT and no links plz ANd Plz HURRRRRy

mars1129 [50]

Answer: The balanced chemical equation is $2KClO_3(s)\rightarrow 2KCl(s)+3O_2(g)$

Explanation:

A balanced chemical equation is one where all the individual atoms are equal on both sides of the reaction. It follows the law of conservation of mass.

For the given unbalanced chemical equation:

$KClO_3(s)\rightarrow KCl(s)+O_2(g)$

On the reactant side:

Atoms of K = 1

Atoms of Cl = 1

Atoms of O = 3

On the product side:

Atoms of K = 1

Atoms of Cl = 1

Atoms of O = 2

To balance the equation, we must balance the atoms by adding 2 infront of both $KClO_3(s)$ and $KCl(s)$ . Also, a coefficient of 3 must be written infront of $O_2(g)$

For the balanced chemical equation:

$2KClO_3(s)\rightarrow 2KCl(s)+3O_2(g)$

5 0

3 years ago

Give the number of lone pairs around the central atom and the geometry of the ion IBr2.

Salsk061 [2.6K]

Answer:

Option E!

Explanation:

If we were to draw the lewis dot structure for IBr2 -, we would first count the total number of valence electrons ( " available electrons " ). Iodine has 7 valence electrons, and so does Bromine, but as Bromine exists in 2, the total number of valence electrons would be demonstrated below;

$7 + 7 * ( 2 ) =\\7 + 14 + 1 =\\22 Electrons$

Don't forget the negative on the Bromine!

Now go through the procedure below;

1 ) Place Iodine in the middle and draw single bonds to each of the bromine.

2 ) Add three lone pairs on each of the Bromine's

3 ) Now we have 6 electrons left, if we were to exclude the electrons shared in the " single bonds. " This can be placed as three lone pairs on Iodine ( central atom )!

The molecular geometry can't be linear, as there are lone pairs on the atoms. This makes it bent.

4 0

3 years ago