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ankoles [38]
3 years ago
9

For every pound a company spends on advertising, it spends £0,75 on its website. Express the

Chemistry
1 answer:
vodomira [7]3 years ago
6 0
It will have a ratio of 4:3
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1)¿Como estoy siendo responsable con el cuidado de mi salud y de los demás , ya sea en casa o si algo a realizar alguna activida
erica [24]

Answer:

The most effective strategy to control the spreading of some infections is through social distancing.

Explanation:

Since we don't have an effective treatment to stop the infection of some pathogens including the recent pandemic SARS-Cov 2 virus, it is imperative to prevent it from spreading

4 0
3 years ago
60 POINTS
Juli2301 [7.4K]

Answer:

PBr3 - Molecule , Polar

N2H2 - Molecule , (Polar in E- form and Non- polar in Z form)

C2H2 - Molecule , Non- Polar

N2 - Molecule , Polar

NCl3 - Molecule , Polar

SiF4 - Molecule , Non- Polar

NH3 - Molecule , Polar

F - Not- Molecule (atom)

H2 - Molecule and Non- Polar

Explanation:

Molecule : these are group of two or more atoms joined by strong force of attraction.

H2  is non- polar because it is homoatomic molecule.(made up of same element)

N2 is non- polar because it is homoatomic molecule.

5 0
3 years ago
Why might people add a base to an acidic lake?
spayn [35]

Answer:

To decrease the algae

Explanation:

Acid lakes have more algae than other lakes

6 0
3 years ago
The image shows two spheres hung from a thin rope. The spheres do not affect each other.
jekas [21]

Answer:

both spheres have a positive charge

8 0
3 years ago
If you start with 1.000 gram sample of the isotope how much time would pass before you have just 0.100 grams of the isotope left
Vadim26 [7]

Answer:

So, you're dealing with a sample of cobalt-60. You know that cobalt-60 has a nuclear half-life of

5.30

years, and are interested in finding how many grams of the sample would remain after

1.00

year and

10.0

years, respectively.

A radioactive isotope's half-life tells you how much time is needed for an initial sample to be halved.

If you start with an initial sample

A

0

, then you can say that you will be left with

A

0

2

→

after one half-life passes;

A

0

2

⋅

1

2

=

A

0

4

→

after two half-lives pass;

A

0

4

⋅

1

2

=

A

0

8

→

after three half-lives pass;

A

0

8

⋅

1

2

=

A

0

16

→

after four half-lives pass;

⋮

Explanation:

now i know the answer

6 0
3 years ago
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