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galben [10]
2 years ago
15

Quintin’s monthly budget is shown on the table below. Quintin wants to start putting $50 in savings each month. If he does, how

much will he have left at the end of the month?
Mathematics
1 answer:
NemiM [27]2 years ago
5 0

Answer:

what is quintin's monthly salary

please post full question

You might be interested in
Y=2+ square root of x-8 solve for x
gizmo_the_mogwai [7]

Answer:

Step-by-step explanation:

y = 2√(x-8)

y² = 4(x-8) = 4x-32

4x = y²+32

x = 0.25y² +8

5 0
3 years ago
High-power experimental engines are being developed by the Stevens Motor Company for use in its new sports coupe. The engineers
Maurinko [17]

Answer:

The 99% of a confidence interval for the average maximum HP for the experimental engine.

(536.46, 603.54)

Step-by-step explanation:

<u><em>Step:-1</em></u>

Given that the mean of the Population = 540HP

Given that the size of the sample  'n' = 9

Given that the mean of the sample = 570HP

Given that the sample standard deviation = 30HP

<u><em>Step(ii):-</em></u>

<u><em>Degrees of freedom = n-1 =9-1 =8</em></u>

<u><em>t₀.₀₀₅ = 3.3554</em></u>

The 99% of a confidence interval for the average maximum HP for the experimental engine.

(x^{-} - t_{\frac{0.01}{2} ,8} \frac{S.D}{\sqrt{n} } ,x^{2}  + t_{\frac{0.01}{2},8 } \frac{S.D}{\sqrt{n} } )

(570-3.354\frac{30}{\sqrt{9} } , 570+3.354\frac{30}{\sqrt{9} } )

(570 - 33.54 , 570+33.54)

(536.46 , 603.54)

<u><em>Final answer</em></u> :-

<em>The 99% of a confidence interval for the average maximum HP for the experimental engine.</em>

<em>(536.46, 603.54)</em>

<em></em>

4 0
3 years ago
Pls help Im confused.​
Oksana_A [137]
The answer is x=13 because the equations equal each other
4 0
2 years ago
Read 2 more answers
PLEASE HELP ASAP!!! CORRECT ANSWER ONLY PLEASE!!!
olasank [31]

Answer:  a_n=2(5)^{n-2}

<u>Step-by-step explanation:</u>

The explicit rule for a geometric sequence is: a_n=a_1(r)^{n-1}\quad \text{where}\ a_1\ \text{is the first term and r is the ratio}

The information provided is: a₁ = \dfrac{2}{5}  and  r = 5

a_n=\dfrac{2}{5}(5)^{n - 1}\\\\.\quad = 2(5)^{n-2}

4 0
3 years ago
Pls help help help help help help ​
Sati [7]

Answer:

-89

Step-by-step explanation:

-89

-89= 10(-7) - 19   ----------->  -70 - 19

5 0
3 years ago
Read 2 more answers
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