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LiRa [457]
3 years ago
14

Please help , would be greatly appreciated !

Mathematics
1 answer:
hoa [83]3 years ago
5 0

Answer:

<em>x </em>= 2

<em>y </em>= -1

Step-by-step explanation:

<em>8x </em>+ <em>2y </em>= 14

<em>2x </em>+ <em>y </em>= 3

In order to find the number <em>x</em> represents, you have to make the number of <em>y </em>for both equations the same. So:

<em>8x </em>+ <em>2y</em><em> </em>= 14

(×2) <em>4x </em>+ <em>2y</em><em> </em>= 6 (×2)

Then, you can cancel the <em>y </em>off both equations, which will leave:

<em>8x </em>= 14

<em>4x </em>= 6

To find <em>4x</em>, you have to find the difference between both equations, so you have to:

14 - 6 = 8

Now that the actual number <em>4x </em>represents is 8, so:

<em>4x </em>= 8

(÷4) <em>x </em>= 2 (÷4)

Now to find <em>y</em>, substitute the letter <em>x</em> with 2:

<em>2x </em>+ <em>y </em>= 3

<em>2 </em>(2)<em> </em>+ <em>y </em>= 3

<em>4 </em>+ <em>y </em>= 3

<em>4 - 3 </em>= -<em>y </em>

<em>1 </em>= -<em>y</em>

(× -) <em>-1 </em>= <em>y </em>(× -)

Answer: <em>x </em>= 2

<em>               y </em>= -1

Hope this helps!  :)

(NOTE: Do you mind marking me as Brainliest?)

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Amount spent on diesel each year = rs 4000

Price of a litre of diesel in the first year = rs 7.50

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Price of a litre of diesel in the third year = rs 8.50

Average cost per litre of diesel = \frac{p_{1} + p_{2} + p_{3}  }{n}

where n is the number of years.

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                                                     = \frac{24}{3}

                                                     = 8

Average cost per litre of diesel is rs 8.00

So that he buys an average of 500 (i.e \frac{4000}{8}) litres every year.

5 0
2 years ago
Grapes are 2.55 per pound and on two separate occasions Dana went to the store to
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Step-by-step explanation:

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Find a 75% confidence interval for the population average weight μ of all adult mountain lions in the specified region. (Round y
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Answer:

75% confidence interval is 91.8±16.66. That is between 75.1 and 108.5 pounds.

Step-by-step explanation:

The question is missing. It is as follows:

Adult wild mountain lions (18 months or older) captured and released for the first time in the San Andres Mountains had the following weights (pounds): 69  104  125  129  60  64

Assume that the population of x values has an approximately normal distribution.

Find a 75% confidence interval for the population average weight μ of all adult mountain lions in the specified region. (Round your answers to one decimal place.)

75% Confidence Interval can be calculated using M±ME where

  • M is the sample mean weight of the wild mountain lions (\frac{69 +104 +125 +129+60 +64}{6} =91.8)
  • ME is the margin of error of the mean

And margin of error (ME) of the mean can be calculated using the formula

ME=\frac{t*s}{\sqrt{N} } where

  • t is the corresponding statistic in the 75% confidence level and 5 degrees of freedom (1.30)
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Thus, ME=\frac{1.30*31.4}{\sqrt{6} } ≈16.66

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