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ANTONII [103]
2 years ago
12

Find the real or imaginary solutions of each equation by factoring #10, #22

Mathematics
1 answer:
mariarad [96]2 years ago
5 0
22)  
(x^2-16)(x^2+4)=0

can you finish?
solve for x (plus and minus because two solution and degreee 4 so total 4 answers  )
x=+-4          x=+-2

hope this helps.

for 10 I know a way but it might confuse you
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Use long division to find the quotient below (30x^3+4x^2-150) / (6x-10)
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Answer:

The answer is

A.5x^2+9x+15

Step-by-step explanation:

kindly find attached the solving for proper understanding and solution flow.

Given Data

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firstly for us to perform the division we need to re write the dividend and include the missing coefficient of x

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2 years ago
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Using your knowledge of exponential and logarithmic functions and properties, what is the intensity of a fire alarm that has a s
Ierofanga [76]

Option B:

I=1.0\times\ 10^{0} \ \text {watts}/ \text m^2}

Solution:

Given sound level = 120 decibel

To find the intensity of a fire alarm:

$\beta=10\log\left(\frac{I}{I_0} \right)

where I_0=1\times10^{-12}\ \text {watts}/ \text m^2}

Step 1: First divide the decibel level by 10.

120 ÷ 10 = 12

Step 2: Use that value in the exponent of the ratio with base 10.

10^{12}

Step 3: Use that power of twelve to find the intensity in Watts per square meter.

$10^{12}=\left(\frac{I}{I_0} \right)

$10^{12}=\left(\frac{I}{1\times10^{-12}\ \text {watts}/ \text m^2} \right)

Now, do the cross multiplication,

I=10^{12}\times1\times\ 10^{-12} \ \text {watts}/ \text m^2}

I=1\times\ 10^{12-12} \ \text {watts}/ \text m^2}

I=1\times\ 10^{0} \ \text {watts}/ \text m^2}

I=1.0\times\ 10^{0} \ \text {watts}/ \text m^2}

Option B is the correct answer.

Hence I=1.0\times\ 10^{0} \ \text {watts}/ \text m^2}.

5 0
3 years ago
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Oliga [24]

Answer:

69a+6

Step-by-step explanation:

Distribute the 6 over the (10a+1) then you get 60a+6. Add the 9a to the 60 giving u 69a then you have the 6 left over making the answer 69a+6

4 0
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