All categories

2 years ago

What are the advantages and disadvantages of common names? ( mention one advantage and one disadvantage)

Chemistry

1 answer:

Novay_Z [31]2 years ago

8 0

Explanation:

Advantages of Common Names

The main advantage of using common plant names is ease of usage and common understanding in certain geographical areas and, conversely, the prevention of confusion among the laymen who do not understand Latin

.What are the disadvantages of common names?

These names may not be same every where in all places so in order to have universally similar name.

Creates confusion among different languages.

Cannot identify one particular species by common names.

You might be interested in

What is the molarity of a solution that contains 0.400 mol HCl in 9.79 l solution?

Maslowich

Answer:

Option B, 0.0409 M

Explanation:

1) Data:

a) M = ?

b) n = 0.400 mol

V = 9.79 liters

2) Formula:

M = n / V (in liters)

3) Solution:

M = 0.400 mol / 9.79 liter = 0.04086 M

Since each data contain 3 significant digits, the answer must be reported with 3 significant digits. So, the correct answer is 0.0409 M, which is the option B.

8 0

3 years ago

Classify the chemical equations as being balanced or not balanced. 2CO 2NO → 2CO2 N2 6CO2 6H2O → C6H12O6 O2 H2CO3 → H2O CO2 2Cu

marissa [1.9K]

Answer:

2CO 2NO → 2CO2 N2 : Balanced

6CO2 6H2O → C6H12O6 : Unbalanced

H2CO3 → H2O CO2 : Balanced

2Cu O2 → CuO : Unbalanced

Explanation:

1.) 2CO 2NO → 2CO2 N2

2 Carbon 2

4 Oxygen 4

2 Nitrogen 2

The amount of atoms of each element on each side of the equation are the same therefore the equation is balanced.

2.) 6CO2 6H2O → C6H12O6 O2

6 Carbon 6

12 Oxygen 8

12 Hydrogen 12

The amount of oxygen atoms is different on both sides of the equation therefore the equation is not balanced.

3.) H2CO3 → H2O CO2

2 Hydrogen 2

1 Carbon 1

3 Oxygen 3

The amount of atoms of each element is the same on both sides of the equation therefore the equation is balanced.

2Cu O2 → CuO.

2 Cu 2

2 O 1

The amount of oxygen atoms is different on both sides of the equation therefore the equation is not balanced.

4 0

2 years ago

5) Calculate the molality of 0.210 mol of KBr dissolved in 0.075kg pure water?

Margaret [11]

Answer:

$\boxed {\boxed {\sf 2.8 \ m }}$

Explanation:

The formula for molality is:

$m=\frac{moles \ of \ solute}{kg \ of \ solvent}$

There are 0.210 moles of KBr and 0.075 kilograms of pure water.

$moles= 0.210 \ mol \\kilograms = 0.075 \ kg$

Substitute the values into the formula.

$m= \frac{ 0.210 \ mol }{0.075 \ kg}$

Divide.

$m= 2.8 \ mol/kg= 2.8 \ m$

The molality is 2.8 moles per kilogram

5 0

2 years ago

Select the correct structure that

Leni [432]

Answer:

Explanation:

its b

8 0

2 years ago

When the temperature of the gas changes from cold to hot, the amount of pressure is ___________.

klio [65]

Assuming constant volume, if you increase temperature, the pressure will increase. So it is B: increasing

6 0

2 years ago

Read 2 more answers