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4 years ago

Which produces oxygen-18 when it undergoes beta decay? A. oxygen-17 B. oxygen-18 C. fluorine-17 D. fluorine-18

Chemistry

1 answer:

inna [77]4 years ago

3 0

Answer:

Option D. fluorine-18

Explanation:

The attached photo gives the explanation.

In the attached photo, A zX represent the atom that will undergo beta decay to produce oxygen–18.

After the calculation, A zX was found to be fluorine–18.

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If the bucket were left outside on a hot day but brought inside before any evaporation occurred, how would the mass be affected?

dangina [55]

It wouldnt because nothing changed

5 0

3 years ago

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A 15.0 mL solution of Sr(OH)2 is neutralized with 38.5 mL of 0.350 M

Darya [45]

Answer:

Molarity of Sr(OH)₂ = 0.47 M

Explanation:

Given data:

Volume of Sr(OH)₂ = 15.0 mL

Volume of HCl = 38.5 mL (0.0385 L)

Molarity of HCl = 0.350 M

Concentration/Molarity of Sr(OH)₂ = ?

Solution:

Chemical equation:

Sr(OH)₂ + 2HCl → SrCl₂ +2H₂O

Number of moles of HCl:

Molarity = number of moles/ volume in L

0.350 M = number of moles/0.0385 L

Number of moles = 0.350 mol/L× 0.0385 L

Number of moles = 0.0135 mol

Now we will compare the moles of HCl with Sr(OH)₂.

HCl : Sr(OH)₂

2 : 1

0.0135 : 1/2×0.0135 = 0.007 mol

Molarity/concentration of Sr(OH)₂:

Molarity = number of moles / volume in L

Molarity = 0.007 mol /0.015 L

Molarity = 0.47 M

7 0

3 years ago

This is the balanced chemical equation for a reaction

Gekata [30.6K]

Answer: C

Explanation:

No explanation

7 0

3 years ago

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What type of energy transfers are these? Any answers are fine

S_A_V [24]

1. C
2. G
3. A
4. I
5. H
6. D
7. B
8. J
9. E
10. F

Hope I helped!

4 0

3 years ago

The air bags in automobiles were once inflated by nitrogen gas generated by the rapid decomposition of

Basile [38]

Answer:

1.57 mol NaN₃

Explanation:

2 NaN₃ (s) → 2 Na (s) + 3 N₂ (g)

First we use PV=nRT to calculate the number of N₂ moles that need to be produced:

P = 1.07 atm

V = 53.4 L

n = ?

R = 0.082 atm·L·mol⁻¹·K⁻¹

T = 23.7 °C ⇒ 23.7 + 273.16 = 296.86 K

Inputing the data:

1.07 atm * 53.4 L = n * 0.082 atm·L·mol⁻¹·K⁻¹ * 296.86

And solving for n:

n = 2.35 mol N₂

Finally we convert N₂ moles into NaN₃ moles, using the stoichiometric coefficients of the balanced reaction:

2.35 mol N₂ * $\frac{2molNaN_3}{3molN_2}$ = 1.57 mol NaN₃

4 0

3 years ago