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vredina [299]
3 years ago
11

Which produces oxygen-18 when it undergoes beta decay? A. oxygen-17 B. oxygen-18 C. fluorine-17 D. fluorine-18

Chemistry
1 answer:
inna [77]3 years ago
3 0

Answer:

Option D. fluorine-18

Explanation:

The attached photo gives the explanation.

In the attached photo, A zX represent the atom that will undergo beta decay to produce oxygen–18.

After the calculation, A zX was found to be fluorine–18.

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Why do different materials/objects have different reactions to fire?​
True [87]

Answer:

Different compounds react with oxygen differently – some contain lots of heat energy while others produce a smaller amount. The reaction with the oxygen may happen very quickly or more slowly. Amount: The amount of fuel available to burn is known as the fuel load.

Explanation:

5 0
2 years ago
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How many grams of nitric acid will react completely with a block of iron metal that is 4.5 cm by 3.0 cm by 3.5 cm, if the densit
denpristay [2]

Balance the equation first: 

2 Fe+6 HNO3→2 Fe(NO3)3+3H2

Then calculate mass of Iron :

4.5×3.0×3.5 cm3(1 mL1 cm3)(7.87 g Fe1 ml)=371.86 g Fe

Now use Stoichiometry:

371.86 g Fe×(1 mol Fe55.85 g Fe)×(6 mol HNO32 mol Fe)=19.97 mol HNO3

Convert moles of nitric acid to grams

19.97 mol HNO3×(63.01 g HNO31 mol HNO3)=1258.3 g HNO3



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2 years ago
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What is the total volume of solution that was dispensed from this burette?
kykrilka [37]

Answer:

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Explanation:

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2 years ago
Which of the following actions will induce an electric current?
pentagon [3]

Answer:

a

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A 6.0 M HCl solution is available. What volume is needed to make 6.00 L of 1.00 M<br> solution?
Ket [755]

Answer:

The volume of the stock solution needed is 1L

Explanation:

Step 1:

Data obtained from the question. This include the following:

Concentration of stock solution (C1) = 6M

Volume of stock solution needed (V1) =?

Concentration of diluted solution (C2) = 1M

Volume of diluted solution (V2) = 6L

Step 2:

Determination of the volume of the stock solution needed.

With the dilution formula C1V1 = C2V2, the volume of the stock solution needed can be obtained as follow:

C1V1 = C2V2

6 x V1 = 1 x 6

Divide both side by 6

V1 = 6/6

V1 = 1L

Therefore, the volume of the stock solution needed is 1L

5 0
2 years ago
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