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azamat
3 years ago
6

If 30mL of 0.5M KOH is needed to neutralize 2M HCl, what was the volume of the acid?

Chemistry
1 answer:
defon3 years ago
3 0
The equation for the reaction between KOH and HCl is as follows
KOH + HCl ---> KCl + H2O
the stoichiometry of KOH to HCl = 1:1
the number of KOH moles reacted = 0.5 mol /1000 cm³ * 30 cm³ 
                                                       = 0.015 mol
the number of HCl moles reacted = number of KOH moles reacted 
therefore HCl moles reacted =  0.015 mol
the molarity of HCl is 0.2 mol/dm³
0.2 mol of HCl in - 1000 cm³
Therefore volume required for 0.015 mol = 1000 cm³ / 0.2 mol * 0.015 mol 
                                                                 = 75 cm³
Therefore 75 cm³ of HCl is required

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The difference between the mass number of an isotope and its atomic number is number of neutrons.

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<h3>What is Atomic number?</h3>

Atomic number is defined as the number of electron in an element.

Atomic number is represented by Z.

<h3>What is Isotopes? </h3>

Isotopes are the element which have same atomic number but have different atomic mass.

Number of proton is equal to number of electrons.

Proton is positively charged, electrons are negativity charge while neutrons are neutral in nature.

Proton and neutrons are present in the nucleus of an element. On the other hand, electron revolves around the nucleus.

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Neutrons of ¹⁶₈O = 16-8 = 8

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3 0
2 years ago
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When you add these up they indicate a mass of 5.33 g for the compound, not 5.80g as you stated in the problem.

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4 years ago
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