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azamat
3 years ago
6

If 30mL of 0.5M KOH is needed to neutralize 2M HCl, what was the volume of the acid?

Chemistry
1 answer:
defon3 years ago
3 0
The equation for the reaction between KOH and HCl is as follows
KOH + HCl ---> KCl + H2O
the stoichiometry of KOH to HCl = 1:1
the number of KOH moles reacted = 0.5 mol /1000 cm³ * 30 cm³ 
                                                       = 0.015 mol
the number of HCl moles reacted = number of KOH moles reacted 
therefore HCl moles reacted =  0.015 mol
the molarity of HCl is 0.2 mol/dm³
0.2 mol of HCl in - 1000 cm³
Therefore volume required for 0.015 mol = 1000 cm³ / 0.2 mol * 0.015 mol 
                                                                 = 75 cm³
Therefore 75 cm³ of HCl is required

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you have 150.0 ml of a 0.807 m solution of ce(no₃)₄. what mass (in grams) of ce(no₃)₄ would be required to make the solution?
Hitman42 [59]

The mass of Ce(NO3)₄ that will be needed to create the solution was 24.16 g (in grams).

<h3>What exactly is the solution?</h3>

A homogenous mixture with one or even more solutes that have been dissolved in the solvent is known as a solution. The material that a solute dissolves in to create a homogenous mixture is known as a solvent. To create a homogenous mixture, a component must dissolve in a solvent.

<h3>What is an illustration of a solution?</h3>

One nanometer or smaller particles are referred to as a solution in a homogeneous mixture made up of two or more components. There are many different types of solutions, including sugar and salt solutions and fizzy water. Each component shows up as a different phase in a solution.

<h3>Briefing:</h3>

Mole of Ce(NO₃)₄ = 0.06225 mole

Molar of Ce(NO₃)₄ = 140.12 + 4[14 + (16×3)]

= 140.12 + 4[14 + 48]

= 140.12 + 4[62]

= 140.12 + 248

= 388.12 g/mol

Mass of Ce(NO₃)₄ = 0.06225 × 388.12

Mass of Ce(NO₃)₄ = 24.16 g

To know more about solution visit:

brainly.com/question/1616939

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1 year ago
b) Explain what happens when a drop of concentrated sugar solution is placed on a rheo leaf peel mounted on a glass slide. Name
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The rheo leaf peel will lose water by osmosis and become flaccid. If the rheo leaf was boiled, this would not happen.

<h3>What is osmosis?</h3>

Across living membranes, water moves from a region of high to a region of low water potential.

Concentrated sugar solutions have low water potential when compared to the cell sap of the cells of rheo leaf peel. Thus, water will move from the rheo leaf peel to the sugar solution.

This will result in the wilting of the leaf peel.

If the leaf peel is boiled, the membranes in the cells die and can no longer function as a selectively permeable interface.

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<h2>Hey There!</h2><h2>_____________________________________</h2><h2>Answer:</h2>

\huge\boxed{Sublimation}

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Sublimation is a process in which the solid molecules gain energy from their surrounding and they now have enough energy to overcome the force of attraction with the neighboring molecules, thus they escape into the surrounding without going through the liquid phase, that means they directly jump to the vapor phase.

<h2>_____________________________________</h2><h2>Endothermic</h2>

Those process which absorb energy from their surrounding to form the product are called endothermic process. Since the SUBLIMATION requires additional energy, it is an endothermic change.

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