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sleet_krkn [62]
3 years ago
10

What separates the inner planets from the outer planets in our solar system?

Chemistry
1 answer:
Anton [14]3 years ago
8 0

Answer:

the answer is B Astroid Belt

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What problems might happen if an unnecessary hurricane warning was issues
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People would rush to the store to buy supplies and there might not be enough for the "last minute noticed" people
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13. Mercury has one of the lowest heat capacities. If 257J of heat are added to 5500g of mercury,the mercury's temp will increas
NikAS [45]

Given:

257J of heat

5500g of mercury

increase by 5.5 degrees Celsius

Required:

Specific heat of mercury

Solution:

H = mCpT

257J = (5500g of mercury) Cp (5.5 degrees Celsius)

Cp = 8.5 x 10^-3 Joules per gram per degree Celsius

3 0
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Which of these properties is the best one to use for identification of an element? 1.the number of neutrons in the atomic nucleu
Verdich [7]

The right answer is 2.

The number of protons contained in a nucleus (called an atomic number) is characteristic of a chemical element. For a given atomic number, the number of neutrons defines different "types" of this element: isotopes. The variation of the number of protons of the nucleus of an atom, during a nuclear reaction for example, causes a change of the element studied.

4 0
3 years ago
Read 2 more answers
Does it take more, less, or the same amount of heat to melt 1.0 kg of ice at 0°C, or to bring 1.0 kg of liquid water at 0°C to t
Murljashka [212]

Answer : It takes less amount of heat to metal 1.0 Kg of ice.

Solution :

The process involved in this problem are :

(1):H_2O(s)(0^oC)\rightarrow H_2O(l)(0^oC)\\\\(2):H_2O(l)(0^oC)\rightarrow H_2O(l)(100^oC)

Now we have to calculate the amount of heat released or absorbed in both processes.

<u>For process 1 :</u>

Q_1=m\times \Delta H_{fusion}

where,

Q_1 = amount of heat absorbed = ?

m = mass of water or ice = 1.0 Kg

\Delta H_{fusion} = enthalpy change for fusion = 3.35\times 10^5J/Kg

Now put all the given values in Q_1, we get:

Q_1=1.0Kg\times 3.35\times 10^5J/Kg=3.35\times 10^5J

<u>For process 2 :</u>

Q_2=m\times c_{p,l}\times (T_{final}-T_{initial})

where,

Q_2 = amount of heat absorbed = ?

m = mass of water = 1.0 Kg

c_{p,l} = specific heat of liquid water = 4186J/Kg^oC

T_1 = initial temperature = 0^oC

T_2 = final temperature = 100^oC

Now put all the given values in Q_2, we get:

Q_2=1.0Kg\times 4186J/Kg^oC\times (100-0)^oC

Q_2=4.186\times 10^5J

From this we conclude that, Q_1 that means it takes less amount of heat to metal 1.0 Kg of ice.

Hence, the it takes less amount of heat to metal 1.0 Kg of ice.

5 0
3 years ago
Why does the designed world change?
Archy [21]
The designed world is changed regularly by inovations and new technology.
Hope I could help.
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3 years ago
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