Answer:
35Cl = 75.9 %
37Cl = 24.1 %
Explanation:
Step 1: Data given
The relative atomic mass of Chlorine = 35.45 amu
Mass of the isotopes:
35Cl = 34.96885269 amu
37Cl = 36.96590258 amu
Step 2: Calculate percentage abundance
35.45 = x*34.96885269 + y*36.96590258
x+y = 1 x = 1-y
35.45 = (1-y)*34.96885269 + y*36.96590258
35.45 = 34.96885269 - 34.96885269y +36.96590258y
0.48114731 = 1,99704989y
y = 0.241 = 24.1 %
35Cl = 34.96885269 amu = 75.9 %
37Cl = 36.96590258 amu = 24.1 %
Answer:
Ammonium chloride, iron ,Sulphur and salt mixed together... they can be separated in the following methods.
1. Ammonium chloride is separated by sublimination... NC4CI is sublimable. Heat the mixture in a china dish and collect the funds of NC4CI (sublimable substance)
2. Bring a magnet close to the remaining mixture. Iron is magnetic substance and thus, it will be attracted towards the magnet. Iron is separated.
3. Sulphur is insoluble in water and salt is soluble. Add water to the remaining mixture and then wait for sedimentation. Separate the sulphur by decantation.
4. Heat the filtered salt solution to obtain salt.
Answer:
Cell Differentiation and Tissue.
Explanation:
tissues are organized communities of cells that work together to carry out a specific function.
Answer:
There is no structure, it depends on what the product contains
Explanation:
In considering a spectroscopic method of identifying a product, if the compound has hydrogen atom then the proton NMR is considered because it contains a nuclear spin.
on the other hand, if it contains carbon, whether Quaternary carbon, tertiary carbon or secondary carbon, then definitely carbon-13 NMR will be considered. and if the compound has a functional group and the group absorbs IR with a particular frequency, then IR will be used in characterizing the compound..
but if the compound when bombarded gives species of radical ion, then Mass spectroscopy will be used in identifying such compound