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4 years ago

Which two elements only need two valence electrons to be happy

Chemistry

1 answer:

Mandarinka [93]4 years ago

6 0

8 to be like noblegasses

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A mixture of pepper and water is a suspension because ________ HELPPPP

malfutka [58]

It doesn't because pepper does not dissolve

7 0

4 years ago

What is the density at 20 degrees Celsius of 12.0 mL of a liquid that has a mass of 4.05g?

zmey [24]

Answer:

<h3>The answer is 0.34 g/mL</h3>

Explanation:

The density of a substance can be found by using the formula

$density = \frac{mass}{volume} \\$

From the question we have

$density = \frac{4.05}{12} \\ = 0.3375$

We have the final answer as

Hope this helps you

5 0

3 years ago

Read 2 more answers

How much positive charge is in 1.4 kg of oxygen? The atomic weight (15.9994 g) of oxygen contains Avogadro’s number of atoms, wi

Cerrena [4.2K]

Answer:

$6.7511\times 10^7\ C$

Explanation:

The atomic weight of oxygen = 15.9994 g

This mass corresponds to 1 mole of the oxygen atoms.

Thus,

15.9994 g mass of oxygen contains $6.02\times 10^{23}$ atoms of oxygen.

1.4 kg = 1400 g ( 1 kg = 1000 g)

So,

1400 g mass of oxygen contains $\frac {6.02\times 10^{23}}{15.9994}\times 1400$ atoms of oxygen.

Number of atoms in 1400 g of oxygen = $526.769754\times 10^{23}$

Also, 1 atom of oxygen contains 8 protons

Charge of 1 proton = + $1.602\times 10^{-19}\ C$

So, Charge on 1 atom of oxygen = $8\times 1.602\times 10^{-19}\ C$

Thus,

Charge on $526.769754\times 10^{23}$ atoms of oxygen = $526.94476\times 10^{23}\times 8\times 1.602\times 10^{-19}\ C=6.7533\times 10^7\ C$

Thus, positive charge in 1.4 kg of oxygen = $6.7511\times 10^7\ C$

5 0

3 years ago

How far would Sara get if she ran for 87 minutes at a speed of .125 miles per minute?

Elza [17]

Answer:

10.875 miles

So 87 minutes

.125 miles per minute

So just multiply int his case

87*.125

You’d get 10.875

7 0

3 years ago

Question 2 the osmotic pressure exerted by a solution is equal to the molarity multiplied by the absolute temperature and the ga

Nutka1998 [239]

<span>1) osmotic pressure exerted by a solution is equal to the molarity multiplied by the absolute temperature and the gas constant r.

Call: P = osmotic pressure; C = molarity; T = absolute temperature

=> P = C * T * r

2) </span><span>write an equation that will let you calculate the molarity c of this solution. your equation should contain only symbols. be sure you define each symbol other than r. </span><span>

</span>=> C = P / (rT)

Answer: C = P / (rT)

6 0

4 years ago