Answer:
Smax = 676 ft
the maximum altitude (height) the rocket will attain during its flight is 676 ft
Step-by-step explanation:
Given;
The height function S(t) of the rocket as;
S(t) = -16t2 + 208t
The maximum altitude Smax, will occur at dS/dt = 0
differentiating S(t);
dS/dt = -32t + 208 = 0
-32t +208 = 0
32t = 208
t = 208/32
t = 6.5 seconds.
The maximum altitude Smax is;
Substituting t = 6.5 s
Smax = -16(6.5)^2 + 208(6.5)
Smax = 676 ft
the maximum altitude (height) the rocket will attain during its flight is 676 ft
Okay so we just need to find out the pattern...
in this case the pattern is adding..
we did
1 + 4 = 5
2 + 5 = 12
we figure this one out by adding 2 and 5 twice so it look like this
2 + 5 + 5 = 12
now moving on to our next one
3 + 6 = 21
so we added 3 and added 6, three times so look
3 + 6 + 6 + 6 = 21
so now
8 + 11 = 96 because we added 8 and added 11, eight times look..
8 + 11 + 11 + 11 + 11 + 11 + 11 + 11 + 11 = 96
so our answer to 8 + 11 is 96!
hope this helps:)
and don't forget 2
MARK ME BRAINLIEST! :D
Answer:
3.50x= t
Step-by-step explanation:
x square feet of teh floor
t= total cost
You will do 82 ÷ 12 and u will get 6.8
