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3 years ago

What are the like terms in the expression below? 3x + 8 + 3y + 8x

Mathematics

1 answer:

Mama L [17]3 years ago

4 0

Answer:

3x and 8x are like terms.

Step-by-step explanation:

Like terms are the terms that share the same variables. They do not have to share the same coefficients - or, in other words - the numbers in front of the variable do not have to be the same. Only the variable has to match.

So, looking at the expression, the only two terms that have the same variable are 8x and 3x, which both have the variable x. Therefore, 3x and 8x are like terms.

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Stuffed animals each weighing 1 over 4 pound are on a scale. The scale shows 1 1 over 2 pounds. How many stuffed animals are on

Anna35 [415]

Answer:

6 stuffed animals

Step-by-step explanation:

if 1/4= 1 then 1x6= 1 1/2

4 0

4 years ago

What is 832.248 rounded to the nearest tenth? A. 830 B. 832.2 C. 832.25 D. 832.3

OleMash [197]

Hi there.

To start, we have to understand where the ten the place is.

Hint: it's 1 place behind the decimal point.

Now we need to know what numbers behind the tenths place make it round up or down.

If the number behind it is 4 or under, round down.

5 & up, round up.

In this case, 830.248 has 2 numbers behind the decimal, so we have to round those THEN the 2 in the tenths place.

830.25 to 830.3

Your answer is D. 830.3

I know this was lengthy, sorry. Just wanted to explain :p

4 0

3 years ago

Joshua traveled 5 hours from City A to City B. The distance between the cities is 260 miles. First he traveled at the constant s

ruslelena [56]

Joshua travelled for 3 hours at the constant speed of 60 mi/h

<h3><u>Solution:</u></h3>

Given that, Joshua traveled 5 hours from City A to City B

The distance between the cities is 260 miles.

First he traveled at the constant speed of 40 mi/h, and then at the constant speed of 60 mi/h.

So, let the number of hours he travelled with 40 mi/h be "n" hours and the distance travelled be "x" miles

Then, the time in which he travelled with 60 mi/h will be 5 – n hours and distance travelled will be 260 – x miles

We have to find how many hours did he travel at the constant speed of 60 mi/h

<em><u>The relation between speed and distance is given as:</u></em>

$\text { distance }=\text { speed } \times \text { time. }$

$\begin{array}{l}{40 \mathrm{mil} / \mathrm{h} \times \mathrm{n} \text { hours }= x \text { miles }} \\\\ {\rightarrow x=40 \mathrm{n} \rightarrow(1)} \\\\ {\text { And } 60 \times(5-\mathrm{n})=260-x \text { miles }}\end{array}$

$\begin{array}{l}{\rightarrow 300-60 n=260-40 n(\text { from }(1))} \\\\ {\rightarrow 60 n-40 n=300-260} \\\\ {\rightarrow 20 n=40} \\\\ {\rightarrow n=2}\end{array}$

So, he travelled 2 hours with speed of 40 mi/h and 5 – 2 = 3 hours with speed of 60 mi/h

Hence, he travelled for 3 hours

5 0

3 years ago

Use the Pythagorean Theorem to find which one of the

marissa [1.9K]

<h3>Hello There!!</h3>

<h3><u>Given</u>:-</h3>

Altitude (AB) = 9cm

Base (BC) = 12cm

Hypotenuse (AC) = ?

$\fbox \text{According To Pythagoras Theorem = }$

$\text{(Hypotenuse)² = (Altitude)² + (Base)²}$

Inserting The Values

$\text{(Hypotenuse)²} =( {9})^{2} + (12) {}^{2} \\ \\ \implies \text{(AC)} {}^{2} = 81 + 144 \\ \\ \implies \text{(AC}) {}^{2} = 225 \\ \\ \implies \text{AC} = \sqrt{225} \\ \\ \implies \text{AC} = 15$

$\therefore \text{Hypotenuse \: (AC)} = 15 \text{cm}$

Option B= <em>15cm</em> is the <u>correct answer</u>

<h3>Hope This Helps</h3>

8 0

2 years ago

Will give brainliest!

Ghella [55]

D tethetjwtjwtjwhwtjwtj

3 0

3 years ago