Y1 is the simplest parabola. Its vertex is at (0,0) and it passes thru (2,4). This is enough info to conclude that y1 = x^2.
y4, the lower red graph, is a bit more of a challenge. We can easily identify its vertex, which is (-4,0), and several points on the grah, such as (2,-3).
Let's try this: assume that the general equation for a parabola is
y-k = a(x-h)^2, where (h,k) is the vertex. Subst. the known values,
-3-(-4) = a(2-0)^2. Then 1 = a(2)^2, or 1 = 4a, or a = 1/4.
The equation of parabola y4 is y+4 = (1/4)x^2
Or you could elim. the fraction and write the eqn as 4y+16=x^2, or
4y = x^2-16, or y = (1/4)x - 4. Take your pick! Hope this helps you find "a" for the other parabolas.
Answer:
A. 0.0049
B. Yes
Step-by-step explanation:
Sample proportion = 0.64
N = 1000
Population proportion = 0.60
We solve for standard deviation
= √p(1-p)/n
= √0.60(1-0.60)/1000
= √0.60x0.40/1000
= √0.00024
= 0.0155
A.
The probability of sample >=0.64
Z>=0.64-0.60/0.0155
Z >= 0.04/0.0155
So z >= 2.5806
Using excel this equal to 0.0049
0.0049 is probability of sample proportion being 0.64 at least.
B.
This answer in a shows that than 60% of households in the united states income class purchased life insurance last year.
Four significant is an answer
because if 0 is the extreme right of decimal place it is significant
and if 0 lies between two significant figure than it is significant like 1.020 is 4 sifnificant and 100 is 1 significant figure
Do you mean the last two? the 9 and 10 are cut off
Note: √a * √a = a
√a * √b = √ab
(√2 + √10)² = (√2 + √10)(√2 + √10)
= √2(√2 + √10) + √10(√2 + √10)
= √2*√2 + √2*√10 + √10*√2 + √10*√10
= 2 + √20 + √20 + 10
= (2 + 10) + (√20 + √20)
= 12 + 2√20
√20 = √(4 *5) = √4 * √5 = 2√5
= 12 + 2√20 = 12 + 2(2√5)
= 12 + 4√5
