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3 years ago

Abcd is a trapezium, calculate the area of abcd

1 answer:

3 0

Answer: Area of a trapezium ABCD = {¹/₂ × (AB + DC) × h} square units. = ¹/₂ × h × (AB + DC) square units. You could have went to google and got the answers cause that what I did dummy

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6r-2(r+8)=11<br> Solve equation

pav-90 [236]

$6r-2(r+8)=11\ \ \ \ |\text{use distributive property}\\\\6r-2(r)-2(8)=11\\\\6r-2r-16=11\ \ \ \ \ |+16\\\\4r=27\ \ \ \ \ |:4\\\\r=6.75$

4 0

3 years ago

Slope -7 and y-intercept (0,9)

faust18 [17]

Answer:

y=-7x+9

Step-by-step explanation:

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2 years ago

Triangle P Q R is shown. The length of P Q is 20 and the length of P R is 12. Angle Q P R is 68 degrees and angle P Q R is 36 de

Tom [10]

Answer:

<h2> 112.3 square units</h2>

Step-by-step explanation:

Find the sketch of the triangle attached.

Area of the triangle = $\frac{1}{2}|PQ| |PR| sinQPR$

Given PQ = 20, PR = 12 and ∠QPR = 68°

Area of the triangle = 1/2 * 20 * 12 * sin68°

Area of the triangle = 120sin68°

Area of the triangle = 112.26 square units

Area of the triangle ≈ 112.3 square units (to the nearest tenth of a square unit)

3 0

2 years ago

Read 2 more answers

help me please!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!

Sunny_sXe [5.5K]

So thi sis really simple since you have an equal sign so

(n/3)-(5n/6)=1/3
to subtract fractions, make the bottom number the same
n/3 times 2/2=2n/6
(2n/6)-(5n/6) or (2n-5n)/6 so
-3n/6=1/3
multiply both sides by 6
-3n=6/3=2
-3n=2
divide both sides by 3
-n=2/3
mmultiply boht by -1
n=-2/3
tada
n=-2/3

6 0

3 years ago

Read 2 more answers

Find the area of the shape shown below.

bija089 [108]

Answer:

i think its 4,800

Step-by-step explanation:

multiply all the sides

5 0

2 years ago

Read 2 more answers