Answer:
Wth IS THIS 2nd grade QUESTION< IT"S LITERALLY ADDIZTION< WAHHH WAHHHW WAHAHHHWHAHAHAH
Step-by-step explanation:
Gonna cry?
Lets put these numbers in order
1,2,3,3,4,5,6,7,8,8,9
Q1 = 3
Q2 (median) = 5
Q3 = 8
the box starts at Q1 and ends at Q3....so left side is 3 and right side is 8
u r correct...it is A
This revolves around exact trig values - no easy way to say this, you just need to memorise them. They are there for sin cos and tan, but I will give you the main tan ones below - note this is RADIANS (always work in them when you can, everything is better):
tan0: 0
tanpi/6: 1/sqrt(3)
tanpi/4: 1
tanpi/3: sqrt(3)
tanpi/2: undefined
Now we just need to equate -2pi/3 to something we understand. 2pi/3 is 1/3 of the way round a circle, so -2pi/3 is 1/3 of the way round the circle going backwards (anticlockwise), so on a diagram we already know it's in the third quadrant of the circle (somewhere between pi and 3pi/2 rads).
We also know it is pi/3 away from pi, so we are looking at sqrt(3) or -sqrt(3) because of those exact values.
Now we just need to work out if it's positive or negative. You can look up a graph of tan and it'll show that the graph intercepts y at (0,0) and has a period of pi rads. Therefore between pi and 3pi/2 rads, the values of tan are positive. Therefore, this gives us our answer of sqrt(3).
The density is 1g/cm³. To calculate density, the equation density=mass/volume is used. You already know the mass, 27g, but you need the volume. The equation for volume is length x width x height. Plug in your side measure 3, to get 3 x 3 x 3, which is 27cm³. Now, just divide the mass by the volume. 27g/27cm³= 1g/cm³
Answer:
it's the fourth one
Step-by-step explanation:
Solve all the problems using exponent rules and the last one equals 632
