First we will find the 11th term
an = a1 + (n-1) * d
a11 = 12 + (11 - 1) * 5
a11 = 12 + 10 * 5
a11 = 12 + 50
a11 = 62
now we use the sum formula...
Sn = (n (a1 + an)) / 2
S11 = (11 (12 + 62)) / 2
S11 = (11 (74)) / 2
S11 = 814/2
S11 = 407
Answer: Sometimes
Step-by-step explanation: Through every 2 points is a line, so it would be sometimes as a line only has a minimum of 2 points.
Answer:
it would be 100
Step-by-step explanation:
if 1=50 and you have 2 then multiple 50 by 2 and that gives you 100
What are the answer choices
.
This is only my opinion. I could be wrong.
My guess is:
Somebody else used that book before you, maybe last year or
the year before, and it was somebody who didn't mind writing
in his book.
One day he didn't have time to write down the homework in his
assignment notebook, so he just circled the homework problems
in his textbook.
