All categories

3 years ago

A type of dripstone formation where the deposits hang from the ceiling of the cave is called a ________________________________.

Physics

1 answer:

Ber [7]3 years ago

4 0

Answer:

Stalactites

Explanation:

these formations are created by dripping water in a cave that is rich in minerals that develop for hundreds of years. stalagmites are also known for their comedic name "cave bacon" I hope this helped!

You might be interested in

a rollercoaster car is moving 19.8 m/s on flat ground when it’s hits the brakes. it decelerates at -3.77 m/s^2 over the next 45.

ehidna [41]

Answer:

3.44 s

Explanation:

Given:

Δx = 45.8 m

v₀ = 19.8 m/s

a = -3.77 m/s²

Find: t

Δx = v₀ t + ½ at²

45.8 = 19.8 t + ½ (-3.77) t²

45.8 = 19.8 t − 1.885 t²

1.885 t² − 19.8 t + 45.8 = 0

t = [ -b ± √(b² − 4ac) ] / 2a

t = [ 19.8 ± √((-19.8)² − 4 (1.885) (45.8)) ] / 2(1.885)

t = [ 19.8 ± √(392.04 − 345.332) ] / 3.77

t = 3.44 or 7.06

The first time, 3.44 seconds, is correct.

The second time is the time it would take the car to return to 45.8 m if it continued decelerating after stopping.

5 0

4 years ago

Everyone open this please!

notsponge [240]

Answer:

yeah i knowwwwwwwwwwwwww

Explanation:

7 0

3 years ago

Read 2 more answers

HELP! DUE TOMORROW!! specify the independent and dependent variables, as well as constants. 4-6! only!

olga55 [171]

Answer:

the variables in a study of a cause-and-effect relationship are called the independent and dependent variables. The independent variables is the cause and the dependent variables is the effects. It's value depends on the changes in the independent variable.

Explanation:

I hope this small infor is helpful

5 0

3 years ago

A vertical wall (8.7 m x 3.2 m) in a house faces due east. A uniform electric field has a magnitude of 210 N/C. This field is pa

Dominik [7]

Answer:

$\phi=4344.72Nm^2/c$

Explanation:

From the question we are told that:

Dimension of Wall:

$(L*B)=(8.7 m * 3.2 m)$

Electric field $B=210 N/C$

Angle $\theta =42 \textdegree North$

Generally the equation for electric Flux is mathematically given by

$\phi=EAcos\theta$

$\phi=210*(8.7*3.2)*cos 42$

$\phi=4344.72Nm^2/c$

3 0

3 years ago

Assume that the loop is initially positioned at θ=30∘θ=30∘ and the current flowing into the loop is 0.500 AA . If the magnitude

labwork [276]

Answer: $\tau=1.03\times 10^{-4}\ N-m$

Torque,

Explanation:

Given that,

The loop is positioned at an angle of 30 degrees.

Current in the loop, I = 0.5 A

The magnitude of the magnetic field is 0.300 T, B = 0.3 T

We need to find the net torque about the vertical axis of the current loop due to the interaction of the current with the magnetic field. We know that the torque is given by :

$\tau=NIAB\ \sin\theta$

Let us assume that, $A=0.0008\ m^2$

$\theta$ is the angle between normal and the magnetic field, $\theta=90^{\circ}-30^{\circ}=60^{\circ}$

Torque is given by :

$\tau=1\times 0.5\ A\times 0.0008\ m^2\times 0.3\ T\ \sin(60)\\\\\tau=1.03\times 10^{-4}\ N-m$

So, the net torque about the vertical axis is $1.03\times 10^{-4}\ N-m$ . Hence, this is the required solution.

4 0

3 years ago