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Dominik [7]
3 years ago
10

An 56 kg sled is being pulled across the snow, at constant speed,by a horizontal force of 15 N, find the coefficient of kinetic

friction, uk between the snow and sled.
Physics
1 answer:
Stolb23 [73]3 years ago
8 0

Answer:

The coefficient of  kinetic friction = 0.026  

Explanation:

An 56 kg sled is being pulled across the snow, at constant speed,by a horizontal force of 15 N.

Here we have to note that the weight is pulled at a constant speed . This means that the net force acting on the weight is zero.

The external force acting on the body is in the forward direction and the friction acts in the backward direction.

Friction increases as the mass of the body increases.

Friction = u_{k}\times m \times g

We now equate this to the external force of 15 N.

15 = u_{k} \times 56 \times 10

u_{k} = \frac{15}{560}

u_{k} = 0.026

The coefficient of  kinetic friction = 0.026  

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A car drives past a pole at 40km/hr. Describe the motion from the point of view of a) the car, and b) the pole. Thanks in advanc
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I was going to beg off until tomorrow, but this one is nothing like those others.
Why, at only 40km/hr, we can ignore any relativistic correction, and just go with Newton.

To put a finer point on it, let's give the car a direction.  Say it's driving North.

a).  From the point of view of the car, its driver, and passengers if any,
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b).  From the point of view of the pole, and any bugs or birds that may be
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c).  A train, steaming North at 80 km/hour on a track that exactly parallels
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The rail motorman, fireman, and conductor all agree on what they have
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Now follow me here . . .

The car and the pole are both seen to be moving south.  BUT ... Since the
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That's what everybody on the train sees.

==============================================

Finally ... since you posed this question as having something to do with your
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You glibly stated in the question that the car is driving along at 40 km/hour ...
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Now I ask you ... was that sloppy or what ? ! ? 

Of course, I came along later and did the same thing with the train, but I am
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The point is . . . the whole purpose of this question, obviously, is to get the student accustomed to the concept that speed has no meaning in and of itself, only relative to something else.  And if the given speed of the car ...40 km/hour ... was measured relative to anything else but the ground on which it drove, as we assumed it was, then all of the answers in (a) and (b) could have been different.

And now I believe that I have adequately milked this one for 50 points worth.


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A 70 kg hunter, standing on frictionless ice, shoots a 42 g bullet horizontally at a speed of 590 m/s . Part A Part complete Wha
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Explanation:

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Using conservation of momentum

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Put the value in the equation

0+0=70\times v_{1}+0.042\times590

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v=-0.354\ m/s

Hence, The recoil velocity is 0.354 m/s.

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