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Dominik [7]
4 years ago
10

An 56 kg sled is being pulled across the snow, at constant speed,by a horizontal force of 15 N, find the coefficient of kinetic

friction, uk between the snow and sled.
Physics
1 answer:
Stolb23 [73]4 years ago
8 0

Answer:

The coefficient of  kinetic friction = 0.026  

Explanation:

An 56 kg sled is being pulled across the snow, at constant speed,by a horizontal force of 15 N.

Here we have to note that the weight is pulled at a constant speed . This means that the net force acting on the weight is zero.

The external force acting on the body is in the forward direction and the friction acts in the backward direction.

Friction increases as the mass of the body increases.

Friction = u_{k}\times m \times g

We now equate this to the external force of 15 N.

15 = u_{k} \times 56 \times 10

u_{k} = \frac{15}{560}

u_{k} = 0.026

The coefficient of  kinetic friction = 0.026  

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Elina [12.6K]

Answer:

La velocidad del haz de electrones es 1.78x10⁵ m/s. Este valor se obtuvo asumiendo que el campo magnético dado (3500007) estaba en tesla y que la fuerza venía dada en nN.

Explanation:

Podemos encontrar la velocidad del haz de electrones usando la Ley de Lorentz:

F = |q|vBsin(\theta)     (1)

En donde:

F: es la fuerza magnética = 100 nN

q: es el módulo de la carga del electron = 1.6x10⁻¹⁹ C

v: es la velocidad del haz de electrones =?

B: es el campo magnético = 3500007 T

θ: es el ángulo entre el vector velocidad y el campo magnético = 90°

Introduciendo los valores en la ecuación (1) y resolviendo para "v" tenemos:

v = \frac{F}{qBsin(\theta)} = \frac{100 \cdot 10^{-9} N}{1.6 \cdot 10^{-19} C*3500007 T*sin(90)} = 1.78 \cdot 10^{5} m/s            

Este valor se calculó asumiendo que el campo magnético está dado en tesla (no tiene unidades en el enunciado). De igual manera se asumió que la fuerza indicada viene dada en nN.

Entonces, la velocidad del haz de electrones es 1.78x10⁵ m/s.  

Espero que te sea de utilidad!                                        

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Explanation:

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What is the objective of playing basagang palayok?the goal what is the goal of playing basang palayok ​
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Answer:

Explanation:

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During the protest, teachers played traditional fiesta games like Palo Sebo and Basagang Palayok “to demonstrate their sacrifices for the country despite the inadequate compensation from the government.”

TDC National Chairperson Benjo Basas said Palo Sebo and Basagang Palayok were symbols of how the government is treating public school teachers.

Palo Sebo, a popular fiesta game in which contestants climb a greased bamboo in order to get the money prize at the top, is the same as the government’s performance-based bonus or PBB, Basas said.

“It promises a cash prize, but teachers and employees need to fight and pull others down in order to be on top,” he explained.

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However, while DepEd expressed support to the plight of public school teachers for salary increase, Luistro enjoined “certain groups not to take any action that greatly affects the delivery of basic services to our learners.”

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A firecracker breaks up into two pieces, one of which has a mass of 200 g and flies off along the x-axis with a speed of 82.0 m/
larisa [96]

Answer:

Total momentum, p = 21.24 kg-m/s

Explanation:

Given that,

Mass of first piece, m_1=200\ g= 0.2\ kg

Mass of the second piece, m_2=300\ g= 0.3\ kg

Speed of the first piece, v_1=82\ m/s (along x axis)

Speed of the second piece, v_2=45\ m/s (along y axis)

To find,

The total momentum of the two pieces.

Solve,

The total momentum of two pieces is equal to the sum of momentum along x axis and along y axis.

p_x=m_1v_1

p_x=0.2\ kg\times 82\ m/s

p_x=16.4\ kg-m/s

p_y=m_2v_2

p_y=0.3\ kg\times 45\ m/s

p_y=13.5\ kg-m/s

The net momentum is given by :

p=\sqrt{p_x^2+p_y^2}

p=\sqrt{16.4^2+13.5^2}

p = 21.24 kg-m/s

Therefore, the total momentum of the two pieces is 21.24 kg-m/s.

4 0
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