Option C
In nuclear fission and fusion the mass defect is the mass lost during the reaction that is converted into energy
<u>Explanation:</u>
Mass defect is the contrast within the estimated mass of the released system and the empirically estimated mass of the nucleus. The nuclear binding energy is acknowledged as mass, and that mass enhances "missing".
This missing mass is described as a mass defect, which is nuclear energy, also acknowledged as the mass discharged from the reaction as any trajectories. The mass defect of a nucleus depicts the mass of the energy adhesive of the nucleus and is the variation amidst the mass of a nucleus and the entirety of the masses of the nucleons of which it is comprised.
Answer:
299,792,458 metres per second
Explanation:
Answer:
4th answer
Explanation:
The gradient of a distance-time graph gives the speed.
gradient = distance / time = speed
Here, the gradient is a constant till 30s. So it has travelled at a constant speed. It means it had not accelarated till 30s. and has stopped moving at 30s.
On Earth, the period of a pendulum is given by:

where L is the length of the pendulum and

is the gravitational acceleration on Earth.
Similarly, the period of the same pendulum on Mars will be

where

is the gravitational acceleration on Mars.
Therefore, if we want to see how does the period of the pendulum on Mars change compared to the one on Earth, we can do the ratio between the two of them:

Therefore, the period of the pendulum on Mars will be 1.63 times the period on Earth.
Answer:
The heat flux between the surface of the pond and the surrounding air is<em> 60 W/</em>
<em> </em>
Explanation:
Heat flux is the rate at which heat energy moves across a surface, it is the heat transferred per unit area of the surface. This can be calculated using the expression in equation 1;
q = Q/A ...............................1
since we are working with the convectional heat transfer coefficient equation 1 become;
q = h (
) ........................2
where q is the heat flux;
Q is the heat energy that will be transferred;
h is the convectional heat coefficient = 20 W/
.K;
is the surface temperature =
C 23°C + 273.15 = 296.15 K;
is the surrounding temperature =
C = 20°C + 273.15 = 293.15 K;
The values are substituted into equation 2;
q = 20 W/
.K ( 296.15 K - 293.15 K)
q = 20 W/
.K ( 3 K)
q = 60 W/
Therefore the heat flux between the surface of the pond and the surrounding air is 60 W/