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3 years ago

Why is it important to learn refusal skills?

Physics

2 answers:

Elena L [17]3 years ago

6 0

I'd say C to avoid situations in which alcohol is present and remain alcohol free

Refusal skills help people, most likely children it helps them avoid participating in risky behaviors and choices. such like alcohol in this case

Refusal skills Helps them resist peer pressure and help them make right choices

Hope that helps alrighty bye now!

ale4655 [162]3 years ago

6 0

Answer: c

Explanation: I just too the quiz

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A material through which electrons can move easily is a what

kirill [66]

Answer:

Electrical conductors

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1 year ago

Identify the law, write the equation and calculate the answer to the problem below.

lyudmila [28]

Find refractive index first

$\\ \rm\Rrightarrow \mu=\dfrac{c}{v}$

$\\ \rm\Rrightarrow \mu=\dfrac{1.0003}{1.33}$

$\\ \rm\Rrightarrow \mu =0.75$

Now

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2 years ago

Rosný bod závisí od ?

WITCHER [35]

Answer:

what did u say and what language are you speaking in

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3 years ago

Elanso [62]

Answer:

Well, their are two answers in their. It would be Ask their Parent for assistance in persuading and Ask for an opportunity to earn extra credit:)

Explanation:

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3 years ago

Read 2 more answers

You have a battery marked " 6.00 V 6.00 V ." When you draw a current of 0.383 A 0.383 A from it, the potential difference betwee

Archy [21]

Answer:

V = 4.81 V

Explanation:

As the potential difference between the battery terminals, is less than the rated value of the battery, this means that there is some loss in the internal resistance of the battery.
We can calculate this loss, applying Ohm's law to the internal resistance, as follows:

$V_{rint} = I* r_{int}$

The value of the potential difference between the terminals of the battery, is just the voltage of the battery, minus the loss in the internal resistance, as follows:

$V = V_{b} - V_{rint} = 5.03 V = 6.0 V - 0.383 A* r_{int}$

We can solve for rint, as follows:

$r_{int} = \frac{V_{b}-V}{I} =\frac{6.0V-5.03V}{0.383A} = 2.53 \Omega$

When the circuit draws from battery a current I of 0.469A, we can find the potential difference between the terminals of the battery, as follows:

$V = V_{b} - V_{rint} = 6.0 V - 0.469 A* 2.53 \Omega= 6.0 V - 1.19 V = 4.81 V$

As the current draw is larger, the loss in the internal resistance will be larger too, so the potential difference between the terminals of the battery will be lower.

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3 years ago