Question

Two tiny conducting sphere are identical and carry charges of -20 μC and +50 μC. They are separated by a distance of 2.50 cm. What is the magnitude of the force that each sphere experiences, and is the force attractive or repulsive?

Answer 1

Answer:

Force between two spheres will be 14400 N

And as the both charges of opposite nature so force will be attractive

Explanation:

We have given two conducting spheres of charges $q_1=-20\mu C=-20\times 10^{-6}C\ and\ q_2=50\mu C=50\times 10^{-6}C$

Distance between the spheres = 2.5 cm =0.025 m

According to coulombs law we know that force between two charges is given by $F=\frac{1}{4\pi \varepsilon _0}\frac{q_1q_2}{r^2}=\frac{Kq_1q_2}{r^2}=\frac{9\times 10^9\times 20\times 10^{-6}\times 50\times 10^{-6}}{0.025^2}=14400N$  

As the both charges of opposite nature so force will be attractive