PLEASE HELP ASAP!!! CORRECT ANSWER ONLY PLEASE!!! I CANNOT RETAKE THIS AND I NEED ALL CORRECT ANSWERS ONLY!!!

Having the correct posture and the degree or severity of braking, acceleration and steering inputs have a direct result on the a

kaheart [24]

Answer: Vehicle Balance

Explanation:

Vehicle balance simply means how the weight of a vehicle is distributed across its tires which connects to the road

It should be noted that there'll be a shift in the balance of a vehicle when the braking, acceleration, or turning bring about a scenario in which the weight of th vehicle moves from one area to another.

8 0

3 years ago

A horizontal force of magnitude 31.3 N pushes a block of mass 4.30 kg across a floor where the coefficient of kinetic friction i

Ostrovityanka [42]

Answer:

$W_{F} = +119.6 J$ : Work done by horizontal force

$W_{Ff} = -96.42 J$ : Work done by friction force

$W_{n} = 23.18 J$ : Net work

Explanation:

Work theory

Work is the product of a force applied to a body and the displacement of the body in the direction of this force.

Thus. The work is equal to the product of the force by the distance (d) and by the cosine of the angle ( α) that exists between the direction of the force (F) and the direction that travels the point or the object that moves:

W= F*d*cosα Formula (1)

The work is positive (W+) if the force goes in the same direction of movement.

The work is negative (W-)if the force goes in the opposite direction to the movement

Net work (Wn)

Net work is defined as the sum of the work done from an initial place to an end point of the trajectory, for each of the individual forces to which the system is subjected.

Problem development

We determine the forces that perform work:

in formula (1 )we observe that the forces that perform work are the forces parallel to displacement. that is α = 0.

For this case they are the horizontal force (F) and the frictional force (Ff)

F=31.3 N : Horizontal force

Ff=μk*N , μk:coefficient of kinetic friction , N : Normal force

N=W

W: block weight W= m*g, m: block mass , g: acceleration due to gravity

W= 4.30 kg* 9.8 m/s² = 42.14 N

Ff= 0.599*42.14 N= 25.24 N : Frictional force

Calculating of the Net work (Wn)

$W_{n} = W_{F} +W_{Ff}$

$W_{F} = 31.3N*3.82 m$

$W_{F} = 119.6 N*m$

$W_{F} = +119.6 J$

$W_{Ff} = -25.24N*3.82m$

$W_{Ff} = -96.42 N* m$

$W_{Ff} = -96.42 J$

$W_{n} = W_{F} +W_{Ff}$

$W_{n} = ( 119.6 -96.42) N*m$

$W_{n} = 23.18 N*m$

$W_{n} = 23.18 J$

8 0

3 years ago

car travels 80 meters due north in 12 seconds then the car turns around and travels 30 Mi do South in 4 seconds calculate the av

Zinaida [17]

Answer:

1) 3.1 m/s

2) 7 m/s

Explanation:

Distance due north = 80 m

Distance due south = 30 m

Distance between north and south = (80 - 30) m = 50 m

Total time = (12 + 4) sec = 16 sec

1) Average speed = 50/16 = 3.1 m/s

2) Average velocity = Total distance/total time = (80 + 30) m/16 s = 110/16 = 7 m/s

8 0

4 years ago

A stone is thrown vertically upward from the roof of the building. Does the position of the stone depend on the location chosen

mel-nik [20]

Yes it depend course you throw the stone at the roof it can't came course it in the roof

7 0

4 years ago

3. 5 m A D с B 0.5 m 1.3 m Figure 2 A beam ADCB has length 5 m. The beam lies on a horizontal step with the end A on the step an

alukav5142 [94]

Based on the principle of moments and the data provided;

the mass of the rod is 20 kg
the smallest value of X of the block that will keep the rod in equilibrium will be 4.054 kg

<h3>What is the principle of moments?</h3>

The principle of moments states that the for a body in equilibrium, the sum of the clockwise moments is equal to the sum of the anticlockwise moments about a point.

Sum of Clockwise moments = Sum of Anticlockwise moments
Moment of a force = mass × perpendicular distance.

At the point where the uniform rod is about to tilt, it is at equilibrium.

Anticlockwise moments = 30 × (1.3 - 0.5) = 24

Clockwise moments = m × (2.5 - 1.3)

where m is the mass of the end

Clockwise moments = m × 1.2

1.2 × m = 24

m = 20 Kg

Therefore, the mass of the rod is 20 kg

Assuming the boy moves to B and a block of mass X is placed at:

Anticlockwise moments = 30 × 1.3 = 39

Clockwise moments = 20 × 1.2 + X × 3.7

Clockwise moments = 24 + 3.7X

39 = 24 + 3.7X

3.7X = 15

X = 4.054 kg

Therefore, the smallest value of X of the block that will enable the boy to stand on the beam at B without the beam tilting is 4.054 kg

Assuming that the block is a particle allowed the assumption that the block touches the rod at only a point.

Learn more about principle of moments at: brainly.com/question/26117248

8 0

2 years ago