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bonufazy [111]
3 years ago
5

Place a small object on the number line below at the position marked zero. Draw a circle around the object. Mark the center of t

his circle with the symbol for “initial position”. Move the object 5.0cm to the right and stop. Label this circle with the correct symbol for “final position.”  (A) What was the initial position of the object?     (B) What is the final position of the object?     (C) What is the distance traveled by the object?     (D) What is the displacement of the object?     (E) Of the three underlined quantities, which are numerically equal?
​

Physics
1 answer:
Viefleur [7K]3 years ago
6 0
It’s is D bc it is and idk you should do it
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the idling engines of a landing turbojet produce forward thrust when operating in a normal manner, but they can produce reverse
Finger [1]

Forward thrust has positive values and reverse thrust has negative values.

Thrust is a sudden push or pull in a certain direction.

a)

Flight speed u = 150 km/h

1 km/h = \frac{1}{3.6} km/s

therefore, 150 km/h =  41.67 km / s

The thrust force represents the horizontal or x-component of momentum equation:

T = m_{exhaust} * U_{exhaust} - U_{flight}

T = 50 * (150 - 41.67)

T = 5416.67 N

Therefore, the value of forward thrust is 5416.67 N.

b)

Now the exhaust velocity is now vertical due to reverse thrust application, then it has a zero horizontal component,

thus thrust equation is:

T = m_{exhaust} * U_{exhaust} - U_{flight}

T = 50 * (0 - 41.67)

T = -2083.5 N

Therefore, the thrust force T is -2083.5 N in the reverse direction.

c)

Now the exhaust velocity and flight velocity is zero, then it has a zero horizontal component, thus thrust is also zero becauseU_{exhaust} = U_{flight} = 0\\

T = 0

Therefore, there is no difference in two velocities in x direction.

The given question is incomplete, the complete question is,

"The idling engines of a landing turbojet produce forward thrust when operating in a normal manner, but they can produce reverse thrust if the jet is properly deflected. Suppose that while the aircraft rolls down the runway at 150 km/h the idling engine consumes air at 50 kg/s and produces an exhaust velocity of 150 m/s.

a. What is the forward thrust of this engine?

b. What are the magnitude and direction (i.e., forward or reverse) if the exhaust is deflected 90 degree without affecting the mass flow?

c. What are the magnitude and direction of the thrust (forward or reverse) after the plane has come to a stop, with 90 degree exhaust deflection and an airflow of 40 kg/s?"

To know more about thrust,

brainly.com/question/14552836

#SPJ1

3 0
1 year ago
-Which of the following wires will have the least resistance?
scoray [572]
The wires that will have the least resistance is :
C. A short thick wire
in order to get the least resistence, you need the wire to be the lowest in length and the highest in Area

hope this helps
7 0
3 years ago
Read 2 more answers
List the following in order from largest to smallest:
LiRa [457]
Organisms, organs, tissues, cell ....

a more specific answer would be:
organism, organ system, organ, tissue, cell, atom
4 0
3 years ago
How much potential energy does a 40-N medicine ball gain when it is lifted 5 m?
777dan777 [17]
We know, Potential Energy = Force * Height
Here, F = 40 N
h = 5 m

Substitute their values, 
U = 40 * 5
U = 200 J

In short, Your Answer would be Option A

Hope this helps!
6 0
3 years ago
A firecracker breaks up into three pieces, one of which has a mass of 200 g and flies off along the x-axis with a speed of 82.0
Mamont248 [21]

Answer:

|P_3|=21.242m/s

Explanation:

From the question we are told that:

Mass m=200g=0.2

Speed v=82.0m/s

Mass M_2=300g=0.3kg

Speed V_2=45.0m/s

Generally the equation for Magnitude of the Third piece is mathematically given by

P_1+P_2+P_3=0

|P_3|=|P_1+P_2|

Where

P_1=m_1v_1

P_1=0.2*82

P_1=16.4kgm/s

And

P_2=0.3*45

P_2=13.5kgm/s

Therefore

|P_3|=\sqrt{16.4^2+13.5^2}

|P_3|=21.242m/s

8 0
3 years ago
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