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anastassius [24]
3 years ago
12

According to the rate law for the reaction, an increase in the concentration of hydronium ion has what effect on this reaction?

Chemistry
1 answer:
aksik [14]3 years ago
8 0

Answer:

The rate of reaction increases.

Explanation:

higher concentration --> more collisions --> rate increases

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Can anyone help on this?
Dennis_Churaev [7]

Answer:

26

Explanation:

5 0
3 years ago
Why do birds have hollow bones​
Minchanka [31]

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6 0
3 years ago
C3H8+5O2 --> 3CO2 + 4H2O
Tresset [83]

Answer:

3, 4 ,1

Explanation:

6 0
3 years ago
The combustion of 0.374 kg of methane in the presence of excess oxygen produces 0.983 kg of carbon dioxide. What is the percent
anyanavicka [17]
Assuming that the combustion formula is
CH4 + 2O2 --> 2H2O + CO2<span>,

That means for every 1 molecule of methane(CH4) there will be one molecule of carbon dioxide(</span>CO2) produced. Methane molecular weight 16, carbon dioxide molecular weight is 44. Then the percent yield should be:
1 * (0.374/ 16) /(0.983/44)= 0.374*44/ 0.983 * 16= 104.6%

You sure the number is correct? Percent yield should not exceed 100%
5 0
4 years ago
At a given temperature, the elementary reaction A − ⇀ ↽ − B , in the forward direction, is first order in A with a rate constant
ZanzabumX [31]

Answer:

0.24

Explanation:

We are given that

Rate constant for A=k=0.0180/s

Rate constant for  B,k'=0.0750/s

We have to find the value of equilibrium constant for the reaction

A\rightleftharpoons B

Equilibrium constant, for k=\frac{k}{k'}

Using the formula

k=\frac{0.0180}{0.0750}=0.24

Hence, the value of the equilibrium constant for the reaction

A\rightleftharpoons B at this temperature=0.24

4 0
3 years ago
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