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stich3 [128]
3 years ago
5

At a given temperature, the elementary reaction A − ⇀ ↽ − B , in the forward direction, is first order in A with a rate constant

of 0.0180 s − 1 . The reverse reaction is first order in B and the rate constant is 0.0750 s − 1 . What is the value of the equilibrium constant for the reaction A − ⇀ ↽ − B at this temperature?
Chemistry
1 answer:
ZanzabumX [31]3 years ago
4 0

Answer:

0.24

Explanation:

We are given that

Rate constant for A=k=0.0180/s

Rate constant for  B,k'=0.0750/s

We have to find the value of equilibrium constant for the reaction

A\rightleftharpoons B

Equilibrium constant, for k=\frac{k}{k'}

Using the formula

k=\frac{0.0180}{0.0750}=0.24

Hence, the value of the equilibrium constant for the reaction

A\rightleftharpoons B at this temperature=0.24

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Answer:

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Explanation:

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Empirical formula = ?

Solution:

Number of gram atoms of C = 37.5 g /12g/mol = 3.125

Number of gram atoms of H = 12.5 g / 1.008 g/mol= 12.4

Atomic ratio:

C                 :            H            

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Molecular formula:

Molecular formula = n (empirical formula)

n = molar mass of compound / empirical formula mass

n = 32  / 16

n = 2

Molecular formula = n (empirical formula)

Molecular formula = 2 ( CH₄)

Molecular formula = C₂H₈

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