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2 years ago

6

The following molecular scenes depict an important reaction in nitrogen chemistry (nitrogen is blue; oxygen is red): Write a bal

anced equation for this reaction. ____N2O5 ___NO2 + ___O2

1 answer:

alexandr1967 [171]2 years ago

3 0

Answer:

2 N2O5 4 NO2 + 1 O2

Explanation:

For the last one you dont really have to add the 1 but you can if its nedded,

since 3 divided by 3 is 1.

You might be interested in

Why do covalent bonds form between elements with similar electronegativity?

sesenic [268]

A COVALENT BOND, FORMS BETWEEN ELEMENTS WITH SIMILAR ELECTRONEGATIVITY AS SHARING OF ELECTRON PAIRS BETWEEN ATOMS IS EASIER AS THEY ARE IDENTICAL.

Explanation:

Bonding atoms with similar electronegativity values form covalent bonds.

A covalent bond, also called a molecular bond, is a chemical bond that involves the sharing of electron pairs between atoms.

Covalent bonds form between two nonmetal atoms with identical or relatively close electronegativity values

Electronegativity is a measure of the tendency of an atom to attract a bonding pair of electrons, also it is the strength an atom has to attract a bonding pair of electrons to itself.

Pure covalent bonds result when two atoms of the same electronegativity bond. This occurs only when two atoms of the same element bond with each other.

6 0

3 years ago

Read 2 more answers

At the county fair, Carrie and Sam climbed up on the carousel horses. Around and around they went; the horses also bobbed up and

grigory [225]

I believe sam's response is correct.
When human is riding a moving target with constant speed over a period of time, we tend to have a visual acceleration perception due to our optical movement.
This make people such as Carrie believes that the carousel horses are accelerating while it actually stayed at constant pace.

3 0

3 years ago

This is what your screen should look like. start with Hydrogen -1 and drag 2 neutrons over the to the nucleus. What happens to t

Alekssandra [29.7K]

Answer:

A tritium is produced.

Explanation:

Combining two additional neutrons to the nucleus of the hydrogen atom makes it a tritium, Hydrogen-3.

neutron is designated ¹₀n; this shows a mass number of 1 and no atomic number

Hydrogen-1 is designated as ₁¹H; a mass number of 1 and atomic number of 1. This particle is actually more like a proton.

Combining both:

₁¹H + 2¹₀n → ³₁H

This is a nuclear reaction and in balancing such reaction equation, mass numbers and atomic numbers must be conserved.

4 0

3 years ago

Consider the equation:

Dmitry [639]

Answer:1. $Rate=k[CHCl_3]^1[Cl_2]^\frac{1}{2}$

2. The rate constant (k) for the reaction is $3.50M^\frac{-1}{2}s^{-1}$

Explanation:

Rate law says that rate of a reaction is directly proportional to the concentration of the reactants each raised to a stoichiometric coefficient determined experimentally called as order.

$rate=k[CHCl_3]^x[Cl_2]^y$

k= rate constant

x = order with respect to $CHCl_3$

y = order with respect to $Cl_2$

n = x+y= Total order

1. a) From trial 1: $0.0035=k[0.010]^x[0.010]^y$ (1)

From trial 2: $0.0069=k[0.020]^x[0.010]^y$ (2)

Dividing 2 by 1 : $\frac{0.0069}{0.035}=\frac{k[0.020]^x[0.010]^y}{k[0.010]^x[0.010]^y}$

$2=2^x,2^1=2^x$ therefore x=1.

b) From trial 2: $0.0069=k[0.020]^x[0.010]^y$ (3)

From trial 3: $0.0098=k[0.020]^x[0.020]^y$ (4)

Dividing 4 by 3: $\frac{0.0098}{0.0069}=\frac{k[0.020]^x[0.020]^y}{k[0.020]^x[0.010]^y}$

$1.4=2^y,2^{\frac{1}{2}}=2^y$ therefore $y=\frac{1}{2}$

$rate=k[CHCl_3]^1[Cl_2]^\frac{1}{2}$

2. to find rate constant using trial 1:

$0.0035=k[0.010]^1[0.010]^\frac{1}{2}$

$k=3.50M^\frac{-1}{2}s^{-1}$

5 0

4 years ago

A _____________reaction mechanism involves loss of a leaving group, formation of a ________ followed by the removal of a proton

Molodets [167]

Answer:

The correct answer is Option C (E1) and Option B (carbocation).

Explanation:

Intramolecular immunity idols are considered as that of the formation mechanism with E1 responses or reactivity.
Reactants with E1 were indeed obligations of both parties, meaning that an E1 reaction was conducted thru all the two stages known as ionization but rather deprotonation. Involves the absence of either an aromatic ring, a carbocation has been generated throughout the ionization solution.

Some other possibilities offered aren't relevant to the procedure outlined. So the above alternative is accurate.

7 0

3 years ago