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devlian [24]
3 years ago
11

Find the value of x in the given right triangle.

Mathematics
1 answer:
VMariaS [17]3 years ago
5 0

Answer:

x = 10.6 units

Step-by-step explanation:

We can use sine to solve this since sine is opposite over hypotnuse.

sin(62) = x/12

.883 = x/12

x = .883 * 12

x = 10.6

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Multiply. Check picture.
VashaNatasha [74]

The answer is 3x^4-13x^3-x^2-11x+6.

Solution:

Use algebraic identity: a^m\times a^n=a^{m+n}

For example: x^2\times x=x^{2+1}=x^3

Given expression (x^2-5x+2) and (3x^2+2x+3).

To multiply these equations.

(x^2-5x+2)\times(3x^2+2x+3)

             =x^2(3x^2+2x+3)-5x(3x^2+2x+3)+2(3x^2+2x+3)

             =(3x^4+2x^3+3x^2)+(-15x^3-10x^2-15x)+(6x^2+4x+6)

             =3x^4+2x^3+3x^2-15x^3-10x^2-15x+6x^2+4x+6

Combine like terms together.

             =3x^4+(2x^3-15x^3)+(3x^2-10x^2+6x^2)-15x+4x+6

             =3x^4-13x^3-x^2-11x+6

(x^2-5x+2)\times(3x^2+2x+3)=3x^4-13x^3-x^2-11x+6

Hence the answer is 3x^4-13x^3-x^2-11x+6.

3 0
3 years ago
HELP QUICK!! solve by substitution and show work please
madam [21]

Solve for the first variable in one of the equations, then substitute the result into the other equation.
Point Form:



x= 1, y= -4

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