Find the value of x in the given right triangle.

Mathematics

1 answer:

VMariaS [17]3 years ago

5 0

Answer:

x = 10.6 units

Step-by-step explanation:

We can use sine to solve this since sine is opposite over hypotnuse.

sin(62) = x/12

.883 = x/12

x = .883 * 12

x = 10.6

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A rectangle has area 64 m2. Express the perimeter of the rectangle as a function of the length L of one of its sides. State the

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A rectangle is a two-dimensional shape with two sets of equal, parallel sides. These dimensions are the length (L) and the width (W). The formula for the rectangle's area is the product of the two dimensions. The formula for perimeter is

P = 2L + 2W

Since
A = LW = 64
W = 64/L
Substituting to the formula for perimeter would be,

P = 2L + 2(64/L)
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Leo made a container to store his camping gear. The container is in the shape of a rectangular prism. The container has material

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(a) What is the capacity of the container?
Volume = length * width * height
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3 years ago

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Required information An article presents a new method for timing traffic signals in heavily traveled intersections. The effectiv

Natasha2012 [34]

Answer:

$652.6-2.01\frac{311.7}{\sqrt{50}}=563.997$

$652.6+2.01\frac{311.7}{\sqrt{50}}=741.203$

So on this case the 95% confidence interval would be given by (563.997;741.203)

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

$\bar X=652.6$ represent the sample mean for the sample

$\mu$ population mean (variable of interest)

s=311.7 represent the sample standard deviation

n=50 represent the sample size

Soltuion to the problem

The confidence interval for the mean is given by the following formula:

$\bar X \pm t_{\alpha/2}\frac{s}{\sqrt{n}}$ (1)

In order to calculate the critical value $t_{\alpha/2}$ we need to find first the degrees of freedom, given by:

$df=n-1=50-1=49$

Since the Confidence is 0.95 or 95%, the value of $\alpha=0.05$ and $\alpha/2 =0.025$ , and we can use excel, a calculator or a table to find the critical value. The excel command would be: "=-T.INV(0.025,49)".And we see that $t_{\alpha/2}=2.01$