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yulyashka [42]
3 years ago
6

Nine times the sum of n and one

Mathematics
1 answer:
Sveta_85 [38]3 years ago
5 0

Answer:

i have no idea what you mean

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Help ASAP (Math) will give brainiest and points!!
nordsb [41]

Answer:

2.17 \times 10^{-1}

Step-by-step explanation:

(7 \times 10 ^{-6}) + 0.26 - (5 \times 10^{-2}) = \frac{7}{10^3} + \frac{26}{10^2}-\frac{5}{10^2}

                                              = \frac{7 + (26 \times 10) - ( 5 \times 10)}{10^3}\\\\=\frac{7 + 260 - 50 }{10^3}\\\\=\frac{217}{10^3}\\\\= 2.17 \times 10^2 \times 10^{-3}\\\\= 2.17 \times 10^{-1}

3 0
2 years ago
Plot the vertices (-2, -8), (-2, 2), and (8, 2).
charle [14.2K]

Answer:

  • (8, -8)
  • 100 square units

Step-by-step explanation:

The diagonals of a rectangle have the same midpoint, so for points A, B, C, D, we must have ...

  (A+C)/2 = (B+D)/2

  D = A + C - B

  D = (-2, -8) +(8, 2) -(-2, 2) = (-2+8+2, -8+2-2)

  D = (8, -8)

__

The side lengths are 2-(-8) = 10, and 8-(-2) = 10. The area is the product of the side lengths, so is 10×10 = 100 square units.

_____

<em>Comment on side lengths</em>

When the end points of one side are on the same vertical line, the length of that side is the difference of y-coordinates. When the points lie on the same horizontal line, the side length is the difference of x-coordinates.

5 0
3 years ago
Read 2 more answers
Rewrite the equation below in standard form.
enyata [817]
Well, the standard equation is in the form:

ax + bx = c (constant).

Thus, x and b must be isolated together on one side with the constant on the other. The equation which satisfies this is:

A. -2x + y = 5
7 0
3 years ago
I need an answer...............................
navik [9.2K]

Answer:

8 i think

Step-by-step explanation:

4 0
2 years ago
3x + y = 19 , and x + 3y = 1. Find the value of 2x + 2y
soldi70 [24.7K]
3x+y=19 \\&#10;x+3y=1 \\ \\&#10;\hbox{add the sides of the equations:} \\&#10;3x+x+y+3y=19+1 \\&#10;4x+4y=20 \\ \\ \hbox{divide both sides by 2:} \\&#10;2x+2y=10

The answer is d. 10.
6 0
3 years ago
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