Answer:
Not really fun facts about hazardous waste
Explanation:
four characteristics of hazardous waste are: ignitability • corrosivity • reactivity • toxicity. These things should be thrown away a proper way to reduce pollution.
You find the molar mass of NaCl first, by adding the weight of both to get 58.44g.
Then you set up the equation with what is given:
2.4mol NaCl and multiply it by 58.44g NaCl to get your answer= 140.256g
Answer:
Bond angle is affected by the presence or addition of lone pair of electrons at the central atom. Due to this, the bonds are displaced slightly inside resulting in a decrease of bond angle, and when you remove an electron domain the bond angle increases.
Explanation:
Answer:
Molality, Solvent, Solute, Mole fraction, Molarity.
Explanation:
The expression of concentration that provides the moles of solute per kilograms of solvent is Molality. This in the only expression referred to the solvent.
A solution is made up of 0.15 grams of sodium chloride in 1 liter of water. For this solution, the Solvent is water. When water is present, it is usually considered the solvent.
A solution is made up of 0.15 grams of sodium chloride in 1 liter of water. For this solution, the Solute is sodium chloride. There can be 1 or more solutes in a solution.
If you place 5 moles of sodium chloride and 4 moles of sucrose into 11 moles of water, the Mole fraction of sodium chloride would be 0.25. The mole fraction is equal to the moles of a substance divided by the total number of moles.
A way to express concentration that provides the moles of solute per liter of solution is Molarity.
Answer:
13.1dm³
Explanation:
Given parameters:
Pressure of gas = 880mmHg
760mmHg = 1 atm
880mmHg will give 1.16atm
Temperature = 303k
Mass of gas = 26.9g
Molar mass of CO₂ = 12 + 2(32) = 44g/mol
Number of moles = mass/molar mass = 26.9/44 = 0.61mole
Unknown:
Volume of the sample = ?
Solution:
To solve this problem, we use the ideal gas equation:
PV = nRT
P is the pressure
V is the volume
n is the number of moles
R is the gas constant = 0.082atmdm³mol⁻¹k⁻¹
T is the temperature
V = 
= 
= 13.1dm³
