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Roman55 [17]
3 years ago
14

How many Sr2+ ions are present in 0.314 moles of Sr3(PO4)2?

Chemistry
1 answer:
zubka84 [21]3 years ago
8 0

Answer:

5.67x10²³ ions

Explanation:

By looking at the molecular formula, we can tell that there are three Sr²⁺ ions per Sr₃(PO₄)₂ molecule.

We <u>convert Sr₃(PO₄)₂ moles into Sr₃(PO₄)₂ molecules</u> by using<em> Avogadro's number</em>:

  • 0.314 moles * 6.023x10²³ = 1.89x10²³ molecules

Finally we <u>multiply that number by 3</u> in order to <em>convert Sr₃(PO₄)₂ molecules to Sr²⁺ ions</em>:

  • 1.89x10²³ * 3 = 5.67x10²³ ions.
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