The 6 in the hundreds place tells you the quotient is at least 100. The non-zero digits in the 1s and 10s places tell you the quotient is more than 100.
Since f(-2) means that our x-value is -2, we can go to that position on the graph and slide up the y-axis to find the intersection this point has with the function graphed.
If I am correct the answer should be that the y value is 2!
Answer: (1a) 250° (1b) 70° (2) see below
<u>Step-by-step explanation:</u>
1a) -110 + 360 (one rotation clockwise) = 250°
1b) 430 - 360 (one rotation counterclockwise) = 70°
2) sec Ф = -8/5 in Quadrant III
Quadrant III identifies that both sin (y) and cos (x) are negative.
sec = r/x --> r = 8, x = -5, and y = -√39
(Use Pythagorean Theorem x² + y² = r² to solve for y)
rationalized = 
(GIVEN)
rationalized = 
NOTE THAT YOU ARE ALLOWED A MAXIMUM OF 3 QUESTIONS PER POST. Please repost #3 and #4 as a different question and I will answer them.
36+48 is the only right answer here