The answer to this question would be: 85/99
In this question, Suzan is taking 8 marble from a bag containing 4 red marbles, 4 green ones, 2 white ones, and 2 purple ones. The total marble in the bag should be: 4+4+2+2= 12. The question is how much the probability to get <4 red marble. In this question, the green, white and purple is not specified so you can join them into not red group. It will be easier to find the probability of "have all the red one" which mean Suzan take 4 red marble and 4 not-red marble<span>
Ways to take 8 marble out of 12=12C5= 12!/4!8!= </span>495
Ways to take 4 red marble out of 4= 4C4= 1
Ways to take 4 not red marble out of 8= 8C4= 8!/4!4!= 70
Probability to <span>have all the red ones= 1*70/495= 14/99
</span>Then the probability does not have all the red ones= 99/99 - 14/99= 85/99
<h3>
Answer: 2z^3</h3>
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Explanation:
The GCF of the coefficients {6, -42, 14} is 2 as it is the largest factor found in each of the three values.
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For the variable portions, we can
- write z^5 as z^3*z^2
- write z^4 as z^3*z^1
- write z^3 as z^3*1
Each time we see z^3 show up, so this is the largest common factor among the three variable terms.
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The two results we got were 2 and z^3
Putting the two results together, we end up with the overall GCF of 2z^3
Y = 3x + 25, because I’m assuming that that you start by renting 25 movies.
y=kx
5=10k
k=10-5
k=5 is the correct answer
Y=f(X)
At y-intercept, X=0
f(X)= 0^3-18(0)^3+107(0)-210
= -210
