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anyanavicka [17]
3 years ago
10

What shifts are occurring internationally in the division of labor and the roles of women in the labor force?

Mathematics
2 answers:
marishachu [46]3 years ago
8 0

Answer:

Women's increased labor force participation represents a significant change in the U.S. economy since 1950. As of 2014, nearly six in ten women aged 16 and older (57.0 percent) worked outside the home (U.S. Bureau of Labor Statistics 2015a), compared with 33.9 percent in 1950 and 43.3 percent in 1970 (Fullerton 1999).

Step-by-step explanation:

hodyreva [135]3 years ago
3 0
In almost every country in the world, men are more likely to participate in labor markets than women. However, these gender differences in participation rates have been narrowing substantially in recent decades. In most countries men tend to participate in labor markets more frequently than women.
All over the world, labor force participation among women of working age increased substantially in the last century.
In some parts of the world, the historical increase in female labor force participation has slowed down or even regressed slightly in recent years.
Women all over the world allocate a substantial amount of time to activities that are not typically recorded as ‘economic activities’. Hence, female participation in labor markets tends to increase when the time-cost of unpaid care work is reduced, shared equally with men, and/or made more compatible with market work.
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Solve the following equations.<br> 3 ⋅ 62^x = 648
gayaneshka [121]

Answer:

x=1.56861

Step-by-step explanation:

62^x=648

By using logarithms it becomes easier to solve this question because of the properties they have

From the property of logarithms

loga^x=xloga

Take logarithms on both sides

log62^x=log648

\Rightarrow xlog62=log648

\Rightarrow x=\frac{log648}{log62}

\Rightarrow x=1.56861

x=1.56861

7 0
3 years ago
Help asap please i don't know the answer lol
Sveta_85 [38]

Answer:

H

Step-by-step explanation:

The parallel line BC divides the sides AD and AE in proportion, that is

\frac{AB}{BD} = \frac{AC}{CE}, that is

\frac{2}{3} = \frac{AC}{4} ( cross- multiply )

3AC = 8 ( divide both sides by 3 )

AC = \frac{8}{3} = 2 \frac{2}{3}, hence

AE = AC + CE

     = 2 \frac{2}{3} + 4 = 6 \frac{2}{3} → H

6 0
3 years ago
What equation do you get when you solve z-m=z+bx for x?
Nimfa-mama [501]
X = -m/b.
Subtract z from both side and you get
-m= bx
Now divide both side by b and you get
-m/b= x
8 0
3 years ago
Read 2 more answers
How do I solve this to find angle G?
VashaNatasha [74]

Answer:

Step-by-step explanation:

The angle at E is 90 degrees.

All tangents of a circle always meet the radius at a 90 degree angle.

90 + 67 + G = 180o    All triangles have 180 degrees. Combine left.

157 + G = 180o           Subtract 157 from both sides.

157 - 157 + G + 180 - 157

G = 23

5 0
3 years ago
Which statement is true
weqwewe [10]
The answers are
a) the domain is all real numbers
d) the input to an exponential function is the exponent
e) the base represents the multiplicative rate of change

hope this helps :)
5 0
3 years ago
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