3 years ago

Question 2 (1 point)

Physics

1 answer:

slava [35]3 years ago

5 0

Both mass and weight would change

You might be interested in

Predict the magnitude of the gravitational force....

Galina-37 [17]

Answer:

a=650.549

b=246.4819

c=38.5261

Explanation:

7 0

2 years ago

Look at a photograph of a fault. notice how the right side appears lower than the left side. this happens when pieces of crust a

dybincka [34]

I believe it’s divergent boundary but I might be wrong

5 0

3 years ago

Read 2 more answers

A radar for tracking aircraft broadcasts a 12 GHz microwave beam from a 2.0-m-diameter circular radar antenna. From a wave persp

My name is Ann [436]

Answer:

915m

Hope this helps.

5 0

3 years ago

A mobile starts with a speed of 250m / s and begins to decelerate at a rate of 3m / s². How fast is it after 45s?

Korvikt [17]

$\large{ \underline{ \underline{ \bf{ \purple{Given}}}}}$

Speed of the mobile = 250 m/s
It starts decelerating at a rate of 3 m/s²
Time travelled = 45s

$\large{ \underline{ \underline{ \bf{ \green{To \: find}}}}}$

Velocity of mobile after 45 seconds

$\large{ \underline{ \underline{ \red{ \bf{Now, \: What \: to \: do?}}}}}$

We can solve the above question using the three equations of motion which are:-

v = u + at
s = ut + 1/2 at²
v² = u² + 2as

So, Here a is acceleration of the body, u is the initial velocity, v is the final velocity, t is the time taken and s is the displacement of the body.

$\large{ \bf{ \underline{ \underline{ \orange{Solution:}}}}}$

We are provided with,

u = 250 m/s
a = -3 m/s²
t = 45 s

By using 1st equation of motion,

⇛ v = u + at

⇛ v = 250 + (-3)45

⇛ v = 250 - 135 m/s

⇛ v = 115 m/s

✤ Final velocity of mobile = 115 m/s

━━━━━━━━━━━━━━━━━━━━

4 0

3 years ago

Magnitude of the normal force exerted by en in the figure below. What is the

vekshin1

Answer:

Explanation:

Reason is that the suitcase is exerted downward and when it moves downward the equation is mgsin tita

6 0

2 years ago