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UkoKoshka [18]
3 years ago
9

Question 2 (1 point)

Physics
1 answer:
slava [35]3 years ago
5 0
Both mass and weight would change
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Need help will mark you the Brainliest
Hatshy [7]
The last one is correct (D)
8 0
3 years ago
4 Points
lbvjy [14]

Answer:

Impulse = 322.5[kg*m/s], the answer is D

Explanation:

This method  it is based on the principle of momentum and the amount of movement; and  used to solve problems involving strength, mass, speed and time.

If units of the SI are used, the magnitude of the impulse of a force is expressed in N * s. however, when remembering the definition of the newton.

N*S=(kg*m/s^{2} )*s = kg*m/s

Now replacing the values on the following equation that express the definition of impulse

Impulse = Force * Time\\\\Impulse = 215 * 1.5 = 322.5 [kg*m/s]

4 0
3 years ago
Read 2 more answers
In this football play the quarterback keeps the ball and goes straight ahead, behind the blocking of the center and the guards.
oksano4ka [1.4K]

Answer:

a

Explanation:

3 0
3 years ago
Based on this electric field diagram, which statement best compares the charge of A with B?
lilavasa [31]

Based on this electric field diagram, the statement which best compares the charge of A with B is "A is negatively charged and B is positively charged. The charge on A is greater than that on B".

<u>Answer:</u> Option A

<u>Explanation:</u>

The charge is quantized represented as elementary charge, about 1.602×10−19 coulombs. Their are two kinds of electric charging: positive and negative (usually transported, separately, by protons and electrons). Like charges repel each other, while attraction occurs among unlike charges. An entity without net charge is considered neutral. If a piece of matter comprises more electrons than protons, it has a negative charge, when there are fewer, it'll have a positive charge and when there are equal amounts, this will be neutral.

4 0
4 years ago
A 1400 kg car drives up a 16 m high hill. The car’s speeds at the bottom and top are 21 m/s and 13 m/s, respectively. If the car
Roman55 [17]

Answer:

Explanation:

mass, m = 1400 kg

height, h = 16 m

initial velocity, u = 21 m/s

final velocity, v = 13 m/s

Work done by engine, We = 80 kJ

Let the work done by the friction force is Wf.

Use the work energy theorem

net work done = change in kinetic energy

work done by engine + work done by friction force + work done by the gravitational force = Change in kinetic energy

80000 + Wf - m x g x h = 0.5 m ( v² - u²)

80000 + Wf - 1400 x 9.8 x 16 = 0.5 x 1400 x ( 169 - 441 )

- 139520 + Wf = - 190400

Wf = 50880 J

4 0
3 years ago
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