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UkoKoshka [18]
3 years ago
9

Question 2 (1 point)

Physics
1 answer:
slava [35]3 years ago
5 0
Both mass and weight would change
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Will mark brainliest! Please help!
djverab [1.8K]

Answer:

30 seconds

Explanation:

A = A02^-(t/hl)

--> ln(A/A0) = -(t/hl)ln2

solving for hl,

hl = -t x ln2 /ln(A/A0)

= -(60 min)xln2/ln(50/200)

= 0.5 min or 30 seconds

3 0
3 years ago
A metal rod with a length of 25.0 cm lies in the xy-plane and makes an angle of 37.5 ∘ with the positive x-axis and an angle of
pashok25 [27]
We are given with the following:
L = 25 cm
θx = <span>37.5</span>°<span>
</span>θy = 52.5°
vx = 6.8 m/s
B = 0.13i - 0.29j - 0.08k

And we are asked for the emf induced in the rod
E = B L v
Substitute the values for B and L into the equation. For v, use the given velocity along x and the angles to convert it to vector form. Then, solve for E.
5 0
3 years ago
If the temperature is 50 degrees and the dew point is 50 degrees, will it rain?
Paul [167]
There is a possibility but not extremely likely
4 0
3 years ago
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Why pilots need to study navigation
masya89 [10]
To know where they’re heading to
3 0
4 years ago
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A 54 kg man holding a 0.65 kg ball stands on a frozen pond next to a wall. He throws the ball at the wall with a speed of 12.1 m
Inessa [10]

Answer:

The velocity of the man is 0.144 m/s

Explanation:

This is a case of conservation of momentum.

The momentum of the moving ball before it was caught must equal the momentum of the man and the ball after he catches the ball.

Mass of ball = 0.65 kg

Mass of the man = 54 kg

Velocity of the ball = 12.1 m/s

Before collision, momentum of the ball = mass x velocity

= 0.65 x 12.1 = 7.865 kg-m/s

After collision the momentum of the man and ball system is

(0.65 + 54)Vf = 54.65Vf

Where Vf is their final common velocity.

Equating the initial and final momentum,

7.865 = 54.65Vf

Vf = 7.865/54.65 = 0.144 m/s

4 0
3 years ago
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