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Amiraneli [1.4K]
2 years ago
15

You and your partner want to investigate how the mass of various sports balls will impact their force as they accelerate down a

ramp. You know that objects with more force will roll farther than objects with less force, so for your investigation you will roll three different types of sports balls down a ramp and measure how far they travel before stopping. You can find information about each ball in the table below.
Please Please PLEASE! help me I need it less then 2 days
Physics
1 answer:
luda_lava [24]2 years ago
6 0

The mass of the ball is inversely proportional to acceleration of a ball.

<h3>What is friction?</h3>

This question is incomplete but I will try to help you the much I can. Friction is the force that opposes motion. Friction depends on the nature of the surfaces in contact.

When the mass of the ball is large, the acceleration of the ball decreases since mass is inversely proportional to acceleration of a body.

Learn more about acceleration: brainly.com/question/2437624

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A jogger accelerates at a constant rate as she travels 5.0
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Answer:

2.0s

Explanation:

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3 years ago
During its swing, a pendulum on a clock has the kinetic energy of 6J and the potential energy of 5J. What formula will you use t
svlad2 [7]

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Potential energy is converted to kinetic energy, which is the energy exerted by a moving object. An active pendulum has the most kinetic energy at the lowest point of its swing when the weight is moving fastest.

Explanation:

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Do acids or bases turn litmus paper red?
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Drupady [299]

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7 0
2 years ago
A 240 N sphere 0.20 m in radius rolls, without slipping 6.0 m downa
Shalnov [3]

Answer:

The angular speed of the sphere at the bottom of the hill is 31.39 rad/s.

Explanation:

It is given that,

Weight of the sphere, W = 240 N

Radius of the sphere, r = 0.2 m

Angle with the horizontal, \theta=28^{\circ}

We need to find the angular speed of the sphere at the bottom of the hill if it starts  from rest.

As per the law of conservation of energy, the total energy at the top is equal to the energy at the bottom.

Gravitational energy = translational energy + rotational energy

So,

mgh=\dfrac{1}{2}mv^2+\dfrac{1}{2}I\omega^2

I is the moment of inertia of the sphere, I=\dfrac{2}{5}mr^2

Also, v=r\omega

h is the height of the ramp, h=l\ sin\theta

mgl\ sin\theta=\dfrac{1}{2}m(r\omega)^2+\dfrac{1}{2}I\omega^2

On solving the above equation we get :

\omega=\sqrt{\dfrac{10gl\ sin\theta}{7r^2}}

\omega=\sqrt{\dfrac{10\times 9.8\times 6\ sin(28)}{7(0.2)^2}}

\omega=31.39\ rad/s

So, the angular speed of the sphere at the bottom of the hill is 31.39 rad/s. Hence, this is the required solution.

6 0
3 years ago
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