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2 years ago

Predict the products of the combustion of methanol, CH3OH(l).

Physics

2 answers:

gregori [183]2 years ago

8 0

Answer:

Carbon dioxide and water

Explanation:

The products of complete combustion are always carbon dioxide and water.

The balanced reaction is:

4 CH₃OH + 3 O₂ → 4 CO₂ + 2 H₂O

morpeh [17]2 years ago

8 0

Answer : The products of the combustion of methanol are, carbon dioxide $(CO_2)$ and water $(H_2O)$

Explanation :

Combustion reaction : It is a type of reaction in which the hydrocarbon react with the oxygen gas to give carbon dioxide and water as products.

The balanced chemical reaction of combustion of methanol $(CH_3OH)$ is :

$2CH_3OH(l)+3O_2(g)\rightarrow 2CO_2(g)+4H_2O(g)$

By the stoichiometry we can say that, 2 mole of methanol react with 3 moles of oxygen gas to give 2 mole of carbon dioxide and 4 moles of water as products.

In this reaction, methanol and oxygen gas are the reactants and carbon dioxide and water are the products.

Therefore, the products of the combustion of methanol are, carbon dioxide $(CO_2)$ and water $(H_2O)$

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$(\vec{a_{G}})_{x}\hat{i}+(\vec{a_{G}})_{y}\hat{j}=0+(\frac{-3gcos\theta}{2l})\hat{k}\times[\frac{lcos\theta}{2}\hat{i}-\frac{lcos\theta}{2}\hat{j}]-\omega^{2}[\frac{lcos\theta}{2}\hat{i}-\frac{lcos\theta}{2}\hat{j}]$

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